本文介绍了如何在C ++中创建Lua表,并将其传递给Lua函数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在C ++中,我有一个地图< string,string> ,包含未知数量的条目。我如何传递给Lua函数,以便Lua函数可以使用数据作为表?
In C++, I have a map<string, string>, containing an unknown number of entries. How can I pass this to a Lua function, so that the Lua function can use the data as a table?
推荐答案想要一个真正的lua表:
if you want a real lua table:
lua_newtable(L); int top = lua_gettop(L); for (std::map::iterator it = mymap.begin(); it != mymap.end(); ++it) { const char* key = it->first.c_str(); const char* value = it->second.c_str(); lua_pushlstring(L, key, it->first.size()); lua_pushlstring(L, value, it->second.size()); lua_settable(L, top); }替换您的地图的正确类型。
with the right types for your map substituted in..
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如何在C ++中创建Lua表,并将其传递给Lua函数?
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