C ++ 11：启动具有成员函数的线程，并将其作为参数

本文介绍了C ++ 11：启动具有成员函数的线程，并将其作为参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

使用此代码，我得到了错误：

Using this code, I got and error :

错误1错误C2064：term不评估为一个函数带1个参数c：\program files ）\microsoft visual studio 11.0 \vc\include\functional 1152 1管道

Error 1 error C2064: term does not evaluate to a function taking 1 arguments c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline

class PipelineJob { private: std::thread *thread; void execute(PipelineJob* object); public: void execute(PipelineJob* object) { } PipelineJob() { this->thread = new std::thread(&PipelineJob::execute, this); } };

我尝试了很多变化，现在如何解决这个问题？

I tried many variation, any one now how to solve this?

推荐答案

为了简单起见，删除模板和指针，这或多或少是你想要的：

Removing the templates and the pointers for simplicity, this is more or less what you would want:

class PipelineJob { private: std::thread thread_; void execute(PipelineJob* object) { ..... } public: PipelineJob() { thread_ = std::thread(&PipelineJob::execute, this, this); } ~PipelineJob() { thread_.join(); } };

请注意， this std :: thread 构造函数：一次为成员函数的隐式第一个参数，第二个为可见参数 PipelineJob * object

Note that this is passed two times to the std::thread constructor: once for the member function's implicit first parameter, the second for the visible parameter PipelineJob* object of the member function.

如果您的执行成员函数不需要外部 PipelineJob 指针，那么你将需要像

If your execute member function does not need an external PipelineJob pointer, then you would need something like

class PipelineJob { private: std::thread thread_; void execute() { ..... } public: PipelineJob() { thread_ = std::thread(&PipelineJob::execute, this); } ~PipelineJob() { thread_.join(); } };