使用此代码,我得到了错误:
Using this code, I got and error :
错误1错误C2064:term不评估为一个函数带1个参数c:\program files )\microsoft visual studio 11.0 \vc\include\functional 1152 1管道
Error 1 error C2064: term does not evaluate to a function taking 1 arguments c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline
class PipelineJob { private: std::thread *thread; void execute(PipelineJob* object); public: void execute(PipelineJob* object) { } PipelineJob() { this->thread = new std::thread(&PipelineJob::execute, this); } };我尝试了很多变化,现在如何解决这个问题?
I tried many variation, any one now how to solve this?
推荐答案为了简单起见,删除模板和指针,这或多或少是你想要的:
Removing the templates and the pointers for simplicity, this is more or less what you would want:
class PipelineJob { private: std::thread thread_; void execute(PipelineJob* object) { ..... } public: PipelineJob() { thread_ = std::thread(&PipelineJob::execute, this, this); } ~PipelineJob() { thread_.join(); } };请注意, this std :: thread 构造函数:一次为成员函数的隐式第一个参数,第二个为可见参数 PipelineJob * object
Note that this is passed two times to the std::thread constructor: once for the member function's implicit first parameter, the second for the visible parameter PipelineJob* object of the member function.
如果您的执行成员函数不需要外部 PipelineJob 指针,那么你将需要像
If your execute member function does not need an external PipelineJob pointer, then you would need something like
class PipelineJob { private: std::thread thread_; void execute() { ..... } public: PipelineJob() { thread_ = std::thread(&PipelineJob::execute, this); } ~PipelineJob() { thread_.join(); } };更多推荐
C ++ 11:启动具有成员函数的线程,并将其作为参数
发布评论