本文介绍了为什么我不能从一个Ajax函数返回的responseText?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
下面是我的Ajax功能的一部分。出于某种原因,我想不通,我可以的警报()的的responseText,但不能的返回的的responseText。任何人都可以帮忙吗?我需要在另一功能中使用该值。
http.onreadystatechange =功能(){ 如果(http.readyState == 4和&安培; http.status == 200){ 返回http.responseText; } }解决方案
您将无法处理,你是从你的异步回调返回的返回值。您应该直接处理的responseText 中的回调,或致电一个辅助函数来处理响应:
http.onreadystatechange =功能(){ 如果(http.readyState == 4和&安培; http.status == 200){ 用handleResponse(http.responseText); } } 功能用handleResponse(响应){ 警报(响应); }Here is part of my Ajax function. For some reason that I cannot figure out, I am able to alert() responseText but not able to return responseText. Can anybody help? I need that value to be used in another function.
http.onreadystatechange = function(){ if( http.readyState == 4 && http.status == 200 ){ return http.responseText; } }解决方案
You will not be able to handle the return value that you are returning from your asynchronous callback. You should handle the responseText within the callback directly, or call a helper function to handle the response:
http.onreadystatechange = function () { if (http.readyState == 4 && http.status == 200) { handleResponse(http.responseText); } } function handleResponse (response) { alert(response); }
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为什么我不能从一个Ajax函数返回的responseText?
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