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问题描述
当我打印一些迭代后,它显示一个大数字,如:4294963846。 code> uint32 a,b; //赋值 uint32 result = a + b; if(result< a){ //溢出}
有一个通用的方法来检查给定数据类型(uint32,int等)的溢出或下溢吗?
我正在这样做:
uint32 a,b ,C; ... //初始化a,b,c if(b您的具体检查将是:
if(a>(cb)){ / / underflow }
Is there a general way to check for an overflow or an underflow of a given data type (uint32, int etc.)?
I am doing something like this:
uint32 a,b,c; ... //initialize a,b,c if(b < c) { a -= (c - b) }When I print a after some iterations, it displays a large number like: 4294963846.
解决方案To check for over/underflow in arithmetic check the result compared to the original values.
uint32 a,b; //assign values uint32 result = a + b; if (result < a) { //Overflow }For your specific the check would be:
if (a > (c-b)) { //Underflow }
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检查C ++中的下溢/溢出?
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