本文介绍了在Swift中转换十进制,二进制和十六进制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
- 十进制转换为二进制
- 二进制到十进制
- 十进制到十六进制
- 十六进制到十进制二进制到十六进制
- 十六进制到二进制
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我已经有了一个基本和冗长的方式但我想找出一个非常有效的方法。
对不起,如果问题有点长...
解决方案字符串和 Int 具有带有 radix (base)的构造函数。结合这些,你可以实现所有的转换:
//十进制到二进制 let d1 = 21 让b1 = String(d1,基数:2) print(b1)//10101 //二进制为十进制 let b2 =10110让d2 = Int(b2,基数:2)! print(d2)// 22 //十进制到十六进制 let d3 = 61 let h1 = String(d3,基数:16) print(h1)//3d //十六进制到十进制 let h2 =a3 let d4 = Int(h2,基数:16)! print(d4)// 163 //二进制为十六进制 let b3 =10101011 let h3 = String(Int(b3,radix:2 )!,基数:16) print(h3)//ab //十六进制到二进制 let h4 =face let b4 = String(Int(h4,radix:16)!,radix:2) print(b4)//1111101011001110
What I want to know is the most code efficient way to convert (in swift 2):
- Decimal to Binary
- Binary to Decimal
- Decimal to Hexadecimal
- Hexadecimal to Decimal
- Binary to Hexadecimal
- Hexadecimal to Binary
I already have a rudimentary and long-winded way of achieving this, but I would like to find out a very efficient way of doing it.
Sorry if the question is a bit long...
解决方案Both String and Int have constructors which take a radix (base). Combining those, you can achieve all of the conversions:
// Decimal to binary let d1 = 21 let b1 = String(d1, radix: 2) print(b1) // "10101" // Binary to decimal let b2 = "10110" let d2 = Int(b2, radix: 2)! print(d2) // 22 // Decimal to hexadecimal let d3 = 61 let h1 = String(d3, radix: 16) print(h1) // "3d" // Hexadecimal to decimal let h2 = "a3" let d4 = Int(h2, radix: 16)! print(d4) // 163 // Binary to hexadecimal let b3 = "10101011" let h3 = String(Int(b3, radix: 2)!, radix: 16) print(h3) // "ab" // Hexadecimal to binary let h4 = "face" let b4 = String(Int(h4, radix: 16)!, radix: 2) print(b4) // "1111101011001110"
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在Swift中转换十进制,二进制和十六进制
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