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问题描述
我有一个带有通配符的模式字符串,比如 X(例如:abc*).
I have a pattern string with a wild card say X (E.g.: abc*).
另外,我有一组字符串,我必须与给定的模式匹配.
Also I have a set of strings which I have to match against the given pattern.
例如:
abf - 假
abc_fgh - 真
abc_fgh - true
abcgafa - 真
abcgafa - true
fgabcafa - 错误
fgabcafa - false
我尝试使用正则表达式,但没有用.
I tried using regex for the same, it didn't work.
这是我的代码
String pattern = "abc*"; String str = "abcdef"; Pattern regex = Patternpile(pattern); return regex.matcher(str).matches();返回错误
有没有其他方法可以让这个工作?
Is there any other way to make this work?
谢谢
推荐答案只需使用 bash 样式模式到 Java 样式模式转换器:
Just use bash style pattern to Java style pattern converter:
public static void main(String[] args) { String patternString = createRegexFromGlob("abc*"); List<String> list = Arrays.asList("abf", "abc_fgh", "abcgafa", "fgabcafa"); list.forEach(it -> System.out.println(it.matches(patternString))); } private static String createRegexFromGlob(String glob) { StringBuilder out = new StringBuilder("^"); for(int i = 0; i < glob.length(); ++i) { final char c = glob.charAt(i); switch(c) { case '*': out.append(".*"); break; case '?': out.append('.'); break; case '.': out.append("\\."); break; case '\\': out.append("\\\\"); break; default: out.append(c); } } out.append('$'); return out.toString(); }是否有等效的java.util.regex 用于glob"类型模式?将通配符转换为正则表达式
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Java 字符串与通配符匹配
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