我想用通配符(*)匹配字符串,其中通配符表示 any。例如:
I would like to match strings with a wildcard (*), where the wildcard means "any". For example:
*X = string must end with X X* = string must start with X *X* = string must contain X此外,某些复合用法例如:
Also, some compound uses such as:
*X*YZ* = string contains X and contains YZ X*YZ*P = string starts with X, contains YZ and ends with P.有没有简单的算法可以做到这一点?我不确定使用正则表达式(尽管有可能)。
Is there a simple algorithm to do this? I'm unsure about using regex (though it is a possibility).
为澄清起见,用户将在上面的过滤器框中键入内容(就像一个简单的过滤器可能),我不希望他们自己编写正则表达式。因此,我可以轻松地从上述表示形式进行转换。
To clarify, the users will type in the above to a filter box (as simple a filter as possible), I don't want them to have to write regular expressions themselves. So something I can easily transform from the above notation would be good.
推荐答案仅供参考,您可以 >使用VB.NET 类似操作员:
Just FYI, you could use the VB.NET Like-Operator:
string text = "x is not the same as X and yz not the same as YZ"; bool contains = LikeOperator.LikeString(text,"*X*YZ*", Microsoft.VisualBasic.CompareMethod.Binary);如果需要,请使用 CompareMethod.Text
您需要使用Microsoft.VisualBasic.CompilerServices; 添加。
You need to add using Microsoft.VisualBasic.CompilerServices;.
更多推荐
用通配符匹配字符串
发布评论