比较JSON阵列

本文介绍了比较JSON阵列的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用的Xbox API返回给定用户gameplayed信息的网站上。它返回JSON格式的结果：

{数据：{玩家代号：主要纳尔逊Gamerpic：HTTPS：\\ / \\ / avatar-ssl.xboxlive \\ /头像\\ /主要％20Nelson \\ /avatarpic-l.pngGameCount：779，TotalEarnedGamerScore：63147，TotalPossibleGamerScore：593465，TotalEarnedAchievements：3429，TotalPossibleAchievements：25498，TotalPercentCompleted：13，PlayedGames：[{ID：1297287449，标题：光环4，URL：HTTP：\\ / \\ / marketplace.xbox \\ / EN-US \\ /标题\\ / 1297287449BoxArt：HTTPS：\\ / \\ / www.xboxleaders \\ / IMG \\ / boxart \\ /1297287449-small.jpgLargeBoxArt：HTTPS：\\ / \\ / www.xboxleaders \\ / IMG \\ / boxart \\ /1297287449-large.jpgEarnedGamerScore：705，PossibleGamerScore：1500年，EarnedAchievements：38，PossibleAchievements：67，PercentageCompleted：56.7，LastPlayed：1363751187}，]}，统计：OK，在：3.818，Authed：假，AuthedAs：空}

我试图创建一个数组，将检查两个不同用户的信息，以便我可以创建一个for循环，只显示这两个用户都玩过游戏的标题和BoxArt（无论完成的百分比或其他变量）。我试过以下code：

＆LT; PHP$玩家代号=使用isset（$ _ GET ['标签']）？ $ _GET ['标签']：空;$ friendtag =使用isset（$ _ GET ['FTAG']）？ $ _GET ['FTAG']：空;$ gamertag2 = urlen code（$玩家代号）;$ friendtag2 = urlen code（$ friendtag）;//获取游戏信息$游戏= json_de code（url_get_contents（'www.xboxleaders/api/games.json?gamertag='.$gamertag2））;$游戏= $游戏 - ＆GT;数据;$ fgames = json_de code（url_get_contents（'www.xboxleaders/api/games.json?gamertag='.$friendtag2））;$ fgames = $ fgames-＆GT;数据;？＆GT;＆LT; PHP$数组1 =数组（$游戏 - ＆GT; PlayedGames-＆GT;标题）;$数组2 =阵列（$ fgames-＆GT; PlayedGames-＆GT;标题）;$结果= array_intersect（$数组1，$数组2）;的print_r（$结果）;？＆GT;

但是，这总是返回一个空集。当我使用$游戏 - > PlayedGames的阵列，它合并两个数组并显示每个所有数据。我真的AP preciate手段，以比较两个用户阵列，这将使我的比赛的两个用户有共同的只是标题和Boxart。

解决方案

函数GAME_TITLE（$游戏）{    返回$游戏 - ＆GT;标题;}$数组1 = array_map（'GAME_TITLE'，$游戏 - ＆GT; PlayedGames）;$数组2 = array_map（'GAME_TITLE'，$ fgames-＆GT; PlayedGames）;$结果= array_intersect（$数组1，$数组2）;的print_r（$结果）;

I'm working on a website utilizing an Xbox API that returns gameplayed information for a given user. It returns results in the json format:

{ "Data": { "Gamertag": "Major Nelson", "Gamerpic": "https:\/\/avatar-ssl.xboxlive\/avatar\/Major%20Nelson\/avatarpic-l.png", "GameCount": 779, "TotalEarnedGamerScore": 63147, "TotalPossibleGamerScore": 593465, "TotalEarnedAchievements": 3429, "TotalPossibleAchievements": 25498, "TotalPercentCompleted": 13, "PlayedGames": [ { "Id": 1297287449, "Title": "Halo 4", "Url": "http:\/\/marketplace.xbox\/en-US\/Title\/1297287449", "BoxArt": "https:\/\/www.xboxleaders\/img\/boxart\/1297287449-small.jpg", "LargeBoxArt": "https:\/\/www.xboxleaders\/img\/boxart\/1297287449-large.jpg", "EarnedGamerScore": 705, "PossibleGamerScore": 1500, "EarnedAchievements": 38, "PossibleAchievements": 67, "PercentageCompleted": 56.7, "LastPlayed": 1363751187 }, ] }, "Stat": "ok", "In": 3.818, "Authed": "false", "AuthedAs": null }

I'm trying to create an array that will check the info of two different users so I can create a for loop to display only the game Titles and BoxArt both users have played (regardless of percentage complete or other variables). I've tried the following code:

<?php $gamertag = isset($_GET['tag']) ? $_GET['tag'] : null; $friendtag = isset($_GET['ftag']) ? $_GET['ftag'] : null; $gamertag2 = urlencode($gamertag); $friendtag2 = urlencode ($friendtag); // Get game information $games = json_decode(url_get_contents('www.xboxleaders/api/games.json?gamertag='.$gamertag2)); $games = $games->Data; $fgames = json_decode(url_get_contents('www.xboxleaders/api/games.json?gamertag='.$friendtag2)); $fgames = $fgames->Data; ?> <?php $array1 = array($games->PlayedGames->Title); $array2 = array($fgames->PlayedGames->Title); $result = array_intersect($array1, $array2); print_r($result); ?>

But this always returns an empty set. When I just use $games->PlayedGames for the arrays, it merges the two array and displays all the data in each. I would really appreciate a means to compare two users array that will give me just the Titles and Boxart of the games two users have in common.

解决方案

function game_title ($game) { return $game->Title; } $array1 = array_map('game_title', $games->PlayedGames); $array2 = array_map('game_title', $fgames->PlayedGames); $result = array_intersect($array1, $array2); print_r($result);