我想将一个Seq的键/值转换为一个Map。序列的第一个元素是保留的,所以对的列表从1开始。
I want to transform a Seq of keys/values to a Map. The first element of the sequence is reserved, so the list of pairs starts in the position 1.
问题是:是否可以实现这个函数使用更多的函数方式吗?
The question is: Is possible to implement this function using a more functional way?
def list2Map(plainMap:Seq[String]) = { var map = Map[String, String]() var idx = 1; while(plainMap.size > idx) { val key = plainMap(idx) idx += 1 val value = plainMap(idx) idx += 1 map = map + (key -> value) } map } assert( list2Map( Seq("reserved slot","key0","value0","key1","value1","key2","value2") ) == Map( ("key0"->"value0"),("key1"->"value1"),("key2"->"value2") ) )我是Scala中的新成员,我知道有很多不同的方法来迭代集合,但是我没有发现forEach方法从元素1开始每次迭代读取两个元素。
I am new in Scala, and I know that there are a lot of different ways to iterate over a collection, but I don't found a forEach way to read two elements per iteration, starting in the element 1.
PS:谢谢大家。我和大家一起学习了很多回应!!
PS: Thanks folks. I am learning a lot with everyone response!!
推荐答案list.drop(1).grouped( 2).map {x => x.head - > x.last} .toMap
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