本文介绍了如何判断一个日期是否在另外两个日期之间?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下代码:
if date in (start, end): print('in between') else: print('No!')date、start和end都是1/1格式的变量.我应该怎么做才能打印出正确的结果?我尝试将日期设置为 10/2,从 3/14 开始,到 11/7 结束,它打印的是否!",这意味着它运行不正确.我想必须将它们格式化为日期格式,然后进行比较.
date, start and end are all variables with the format of 1/1. What should I do to have it print out the right result? i tried date as 10/2, start as 3/14 and end as 11/7 and it's print 'No!', which means it's not running right. I guess have to format them to a date format and then compare them.
推荐答案既然你还不满意,我再给你一个答案.不使用日期时间和年份.
As you are still not satisfied, I have another answer for you. Without using datetime and year.
它只是使用内置元组并比较它们:
It just uses built-in tuples and comparing them:
d1 = (3, 28) d2 = (3, 31) d3 = (4, 2) if d1 < d2 < d3: print("BETWEEN!") else: print("NOT!")您可以轻松地创建这样的元组:
You can create tuple like these easily:
day = 16 month = 4 d = (month, day)更多推荐
如何判断一个日期是否在另外两个日期之间?
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