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问题描述
我批量更新大量对象,想要忽略任何重复的对象。 这是什么最好的方法?
我的理解是,如果抛出 ConstrainViolationException ,批次中的所有其他对象将 / strong>。
解决方案 p $ p> private void saveBatch(){ StatelessSession session = sessionFactory.openStatelessSession(); 事务tx = session.beginTransaction(); try { for(Object t:batchList){ session.insert(t); } txmit(); } catch(ConstraintViolationException e){ log.info(批量复制...单独保存); tx.rollback(); session.close(); saveIndividually(); return; } session.close(); batchList.clear(); } private void saveIndividually(){ StatelessSession session = sessionFactory.openStatelessSession(); for(Object t:batchList){ Transaction tx = session.beginTransaction(); session.insert(t); try { txmit(); } catch(ConstraintViolationException e){ tx.rollback(); log.warn(Ignoring duplicate:+ t); } } session.close(); batchList.clear(); }
I'm updating a very large number of objects in batches and want to ignore any duplicates. What is the best way of doing this?
My understanding is that if a ConstrainViolationException is thrown all the other objects in the batch will NOT be persisted.
解决方案This was my solution:
private void saveBatch() { StatelessSession session = sessionFactory.openStatelessSession(); Transaction tx = session.beginTransaction(); try { for (Object t : batchList) { session.insert(t); } txmit(); } catch (ConstraintViolationException e) { log.info("Duplicate in batch...save individually"); tx.rollback(); session.close(); saveIndividually(); return; } session.close(); batchList.clear(); } private void saveIndividually() { StatelessSession session = sessionFactory.openStatelessSession(); for (Object t : batchList) { Transaction tx = session.beginTransaction(); session.insert(t); try { txmit(); } catch (ConstraintViolationException e) { tx.rollback(); log.warn("Ignoring duplicate: " + t); } } session.close(); batchList.clear(); }
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Hibernate使用constraintviolationexception进行批量更新
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