我要重组下面使用Squeel查询。我想做到这一点,这样我可以链上的运营商,并重复使用的逻辑在查询中的不同部分。
User.find_by_sql(选择 用户。*, usersputed_metric, users.age_in_seconds, (usersputed_metric / age_in_seconds)作为compound_computed_metric 从 ( 选择 用户。*, (users.id * 2)作为computed_metric, (提取物(从现在的时代()) - 提取物(纪元从users.created_at))作为age_in_seconds 从用户 )为用户)
的查询有向所有工作在DB和不应该是一个混合的Ruby溶液,因为其具有定购和切片的记录百万
我设置的问题,以便它应该运行较正常用户表,这样就可以用替代品进行播放。
在一个可以接受的答案限制- 查询应返回用户对象,所有正常的属性
- 在每个用户对象还应包括 extra_metric_we_care_about , age_in_seconds 和 compound_computed_metric
- 查询不应只是打印出一个字符串在多个地方复制任何逻辑 - 我想避免做同样的事情两次
- [更新]查询都应该做,能够在数据库中,这样的结果集,可能包括数以百万计的记录可以返回到Rails的 之前订购和切片在DB
- [更新]应该为一个Postgres数据库的解决方案
下面的解决方案不工作,但它显示了优雅是我希望实现的类型
类用户的LT;的ActiveRecord :: Base的 #这不工作 - 它只是说明了什么我想达到 高清self.w_all_additional_metrics 选择{ ['*', computed_metric, age_in_seconds, (computed_metric / age_in_seconds)。如(compound_computed_metric) } {。从User.wpound_computed_metric.w_age_in_seconds} 结束 高清self.w_computed_metric 其中{'(ID * 2)作为computed_metric'} 结束 高清self.w_age_in_seconds 其中{(摘录(时代从现在开始()) - 提取物(纪元从created_at))作为age_in_seconds'} 结束 结束您应该能够对现有的数据库运行此
请注意,我已经有点做作的问题,以便您可以使用现有的用户类,并用它在你的控制台玩。的
修改我有2 sulutions你的情况。我的数据库是MySQL和我简化您的code的演示,我觉得你可以扩展它。
首先是Squeel的方式,我在Squeel混合筛选和ActiveRecord的查询从。 我安装PostgreSQL和测试,我的解决方案就在刚才,这似乎很难用squeel和划时代的在一起,但我发现在PostgreSQL中的另一种方式,它被称为date_part数。我还修改了SQL和减少计算的重复:
类用户的LT;的ActiveRecord :: Base的 筛:w_computed_metric做 (ID * 2)。如(computed_metric) 结束 筛:w_age_in_seconds做 (date_part数('划时代',now.func) - date_part数('划时代',created_at))。如(age_in_seconds) 结束 筛:w_compound_computed_metric做 (computed_metric / age_in_seconds)。如(compound_computed_metric) 结束 高清self.subquery 选择{['*',过筛(w_computed_metric),过筛(w_age_in_seconds)]} 结束 高清self.w_all_additional_metrics 选择{['*',过筛(w_compound_computed_metric)]}从((#{subquery.to_sql})的用户)。 结束 结束
它产生的SQL:
SELECT *,用户。computed_metric/用户。age_in_secondsAS compound_computed_metric FROM(SELECT *, 用户,ID* 2 AS computed_metric, date_part数(时代,现在()) - date_part数(时代,用户,created_at。)AS age_in_seconds从用户 )用户您可以使用控制台对其进行测试:
> User.w_all_additional_metrics.firstputed_metric => 2 > User.w_all_additional_metrics.first.age_in_seconds => 633.136693954468 > User.w_all_additional_metrics.firstpound_computed_metric => 0.00315887551471441
二是ActiveRecord的方式,因为你的SQL是不是很复杂的,所以你可以连它的ActiveRecord查询,这是不够的一些范围:
类用户的LT;的ActiveRecord :: Base的 适用范围:w_computed_metric,PROC {选择('ID * 2为computed_metric')} 适用范围:w_age_in_seconds,PROC {选择(提取物(从历元(NOW() - created_at))为age_in_seconds')} 适用范围:w_compound_computed_metric,PROC {选择(computed_metric / age_in_seconds为compound_computed_metric')} 高清self.subquery 选择(*)。w_computed_metric.w_age_in_seconds 结束 高清self.w_all_additional_metrics subquery.w_compound_computed_metric.from((#{subquery.to_sql})用户) 结束 结束这生成的SQL语句:
SELECT *,ID * 2为computed_metric, 提取物(从历元(NOW() - created_at))作为age_in_seconds, computed_metric / age_in_seconds为compound_computed_metric 从 ( 选择 * ID * 2为computed_metric, 提取物(从(时代今() - created_at))作为age_in_seconds 从 用户 )用户 ORDER BY compound_computed_metric降序 LIMIT 1
希望它符合您的要求:)
I want to restructure the query below using Squeel. I'd like to do this so that I can chain the operators in it and re-use the logic in the different parts of the query.
User.find_by_sql("SELECT users.*, usersputed_metric, users.age_in_seconds, ( usersputed_metric / age_in_seconds) as compound_computed_metric from ( select users.*, (users.id *2 ) as computed_metric, (extract(epoch from now()) - extract(epoch from users.created_at) ) as age_in_seconds from users ) as users")The query has to all operate in the DB and should not be a hybrid Ruby solution since it has to order and slice millions of records.
I've set the problem up so that it should run against a normal user table and so that you can play with the alternatives to it.
Restrictions on an acceptable answer- the query should return a User object with all the normal attributes
- each user object should also include extra_metric_we_care_about, age_in_seconds and compound_computed_metric
- the query should not duplicate any logic by just printing out a string in multiple places - I want to avoid doing the same thing twice
- [updated] The query should all be do-able in the DB so that a result set that may consist of millions of records can be ordered and sliced in the DB before returning to Rails
- [updated] The solution should work for a Postgres DB
The solution below doesn't work but it shows the type of elegance that I'm hoping to achieve
class User < ActiveRecord::Base # this doesn't work - it just illustrates what I want to achieve def self.w_all_additional_metrics select{ ['*', computed_metric, age_in_seconds, (computed_metric / age_in_seconds).as(compound_computed_metric)] }.from{ User.wpound_computed_metric.w_age_in_seconds } end def self.w_computed_metric where{ '(id *2 ) as computed_metric' } end def self.w_age_in_seconds where{ '(extract(epoch from now()) - extract(epoch from created_at) ) as age_in_seconds' } end endYou should be able to run this against your existing database
Please note that I've somewhat contrived the problem so that you can use your existing User class and play with it in your console.
EDIT解决方案
I have 2 sulutions in your case. My database is mysql, and I simplify your code for demo, I think you can extend it.
The first is Squeel way, I mixed "sift" in Squeel and "from" in ActiveRecord Query. I installed postgresql and tested my solution just now, It seems hardly to use "squeel" and "epoch from" together, but I found an alternative way in postgresql, it called "date_part". I also modified the sql and reduced the duplications of calculation:
class User < ActiveRecord::Base sifter :w_computed_metric do (id * 2).as(computed_metric) end sifter :w_age_in_seconds do (date_part('epoch' , now.func) - date_part('epoch', created_at)).as(age_in_seconds) end sifter :w_compound_computed_metric do (computed_metric / age_in_seconds).as(compound_computed_metric) end def self.subquery select{['*', sift(w_computed_metric) , sift(w_age_in_seconds)]} end def self.w_all_additional_metrics select{['*', sift(w_compound_computed_metric)]}.from("(#{subquery.to_sql}) users") end endIt produced the sql:
SELECT *, "users"."computed_metric" / "users"."age_in_seconds" AS compound_computed_metric FROM (SELECT *, "users"."id" * 2 AS computed_metric, date_part('epoch', now()) - date_part('epoch', "users"."created_at") AS age_in_seconds FROM "users" ) usersYou can test it using the console:
> User.w_all_additional_metrics.firstputed_metric => "2" > User.w_all_additional_metrics.first.age_in_seconds => "633.136693954468" > User.w_all_additional_metrics.firstpound_computed_metric => "0.00315887551471441"The second is ActiveRecord way, because your sql is not very complicate, so you can chain it in ActiveRecord Query, it's enough with some scopes :
class User < ActiveRecord::Base scope :w_computed_metric, proc { select('id*2 as computed_metric') } scope :w_age_in_seconds, proc { select('extract (epoch from (now()-created_at)) as age_in_seconds') } scope :w_compound_computed_metric, proc { select('computed_metric/age_in_seconds as compound_computed_metric') } def self.subquery select('*').w_computed_metric.w_age_in_seconds end def self.w_all_additional_metrics subquery.w_compound_computed_metric.from("(#{subquery.to_sql}) users") end endThis produces the following SQL:
SELECT *, id*2 as computed_metric, extract (epoch from (now()-created_at)) as age_in_seconds, computed_metric / age_in_seconds as compound_computed_metric FROM ( SELECT *, id*2 as computed_metric, extract (epoch from (now()-created_at)) as age_in_seconds FROM "users" ) users ORDER BY compound_computed_metric DESC LIMIT 1Hope it meets your requirement :)
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你将如何做到这一点的Rails使用Squeel子查询?
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