我有一个字符数组:
char[] a = {'h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd'};我目前的解决办法是做
My current solution is to do
String b = new String(a);但肯定有这样做的更好的办法?
But surely there is a better way of doing this?
推荐答案没有,该解决方案是完全正确和非常小的。
No, that solution is absolutely correct and very minimal.
不过请注意,这是一个非常不寻常的情况:因为字符串是专门在Java中处理,甚至foo的实际上是一个字符串。所以不需要在正常code代表将字符串分割成单独的字符和他们一起回来的必要。
Note however, that this is a very unusual situation: Because String is handled specially in Java, even "foo" is actually a String. So the need for splitting a String into individual chars and join them back is not required in normal code.
比较这对C / C ++,其中foo的你的字符 S按零终止的包它们之间的字节一边和字符串在另一边,许多因转换遗留做的方法。
Compare this to C/C++ where "foo" you have a bundle of chars terminated by a zero byte on one side and string on the other side and many conversions between them due do legacy methods.
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