XCode无法识别环境变量

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我使用以下脚本在OSX Yosemite 10.10.5上运行XCode(7.0.1 7A1001):

I use the following script to run XCode (7.0.1 7A1001) on OSX Yosemite 10.10.5:

export FOO=bar #this should not be necessary, but just in case launchctl setenv FOO bar #should make it visible to all GUI applications (=XCode) open -a xcode

然后，我打开一个包含两个项目的工作区: App1 和 App2 .在两个项目中，我都将$(HOME)/$(FOO)放在 Header Search Paths 字段中.

I then open a workspace with two projects: App1 and App2. In both projects I put $(HOME)/$(FOO) in the Header Search Paths field.

• 在 App1 中，按预期将其解析为/Users/ohads/bar.
• 在 App2 中，它解析为/Users/ohads/-请注意如何解析HOME变量，但不能解析FOO变量.

• In App1 it is resolved to /Users/ohads/bar as expected.
• In App2 it is resolved to /Users/ohads/ - note how the HOME variable is resolved, but the FOO variable is not.

这是怎么回事?为什么会有差异?如何使FOO在App2中工作-我缺少一些特殊的标志或声明吗?

What's going on here? Why the discrepancy? How can I make FOO work in App2 - is there some special flag or declaration I'm missing?

顺便说一句，似乎还不够怪异，即使我仅使用export，App1仍然可以工作(与launchctl相对，后者应该用于GUI应用程序，因为export应该只影响现金应用程序)

BTW, as if that's not weird enough, App1 works even when I only use export (as opposed to launchctl which is what one should use for GUI applications, seeing as export should only affect cash applications).

推荐答案

看起来与新的XCode 7行为.为了使XCode使用环境变量，必须发出以下命令:

Looks like this has to do with new XCode 7 behavior. In order for XCode to use environment variables the following command must be issued:

$ defaults write com.apple.dt.Xcode UseSanitizedBuildSystemEnvironment -bool NO

发出此命令后，export和launchctl均起作用(根据chepner的评论).我只能猜测它是在 App1 中工作的，因为它是在较旧的XCode版本中创建的.

Once this command is issued, both export and launchctl work (as per chepner's comment). I can only guess it was working in App1 because it was created in an older XCode version.