根据可能为null的属性对数组排序

本文介绍了根据可能为null的属性对数组排序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！问题描述

我有一个对象数组:

let items = [ { name: 'eric', value: 1 }, { name: 'bob', value: 4 }, { name: 'michael', value: 0 }, { name: 'john', value: 3 }, { name: 'brad', value: null }, { name: 'martin', value: 2 }, { name: 'chris', value: null } ];

我想对数组进行排序，以便可以通过值"属性对对象进行排序，如果它为null，则将对象放在数组的底部:

{ name: 'michael', value: 0 }, { name: 'eric', value: 1 }, { name: 'martin', value: 2 }, { name: 'john', value: 3 }, { name: 'bob', value: 4 }, { name: 'brad', value: null }, { name: 'chris', value: null }

->

我已经尝试过了

items.sort((a, b) => { return (a.orde ===null)-(b.ordre===null) || +(a.ordre>b.ordre)||-(a.ordre<b); });

但是似乎不起作用

建议?

解决方案

您可以先检查null，然后按值排序.

.as-console-wrapper { max-height: 100% !important; top: 0; }

I ve an array of objects :

let items = [ { name: 'eric', value: 1 }, { name: 'bob', value: 4 }, { name: 'michael', value: 0 }, { name: 'john', value: 3 }, { name: 'brad', value: null }, { name: 'martin', value: 2 }, { name: 'chris', value: null } ];

i want to sort my array so that the objects can be sorted by the "value" attribute , and if it's null , make the object in the bottom of the array :

{ name: 'michael', value: 0 }, { name: 'eric', value: 1 }, { name: 'martin', value: 2 }, { name: 'john', value: 3 }, { name: 'bob', value: 4 }, { name: 'brad', value: null }, { name: 'chris', value: null }

->

i ve tried this ;

items.sort((a, b) => { return (a.orde ===null)-(b.ordre===null) || +(a.ordre>b.ordre)||-(a.ordre<b); });

But seems that it's not working

Suggestions ?

解决方案

You could check for null first and then sort by the value.

.as-console-wrapper { max-height: 100% !important; top: 0; }

更多推荐

根据可能为null的属性对数组排序