数组中有多少个奇数和偶数

本文介绍了数组中有多少个奇数和偶数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我用一些数字创建了一个数组.我想找出多少个偶数和多少个奇数这个数组.我必须像这样打印出来:(这只是一个例子)

I have created an Array with some numbers. I want to find out how many even, and how many odd numbers it is in this Array. I have to print it out like this: (this is just an example)

偶数:6

奇数:7

我需要进行一个循环，以计算掉多少个偶数和奇数.

I need to make a loop that count up how many it is off even and odd numbers.

这是我到目前为止所拥有的

This is what I have so far

<script> window.onload = run; var tall = [5,10,15,20,25,30,35,40,45,50]; function run() { tall = [5,10,15,20,25,30,35,40,45,50]; liste(tall); } function liste(arr) { var sumOdd = 0; // Odd 1, 3, 5 etc.. var sumPar = 0; // Even 2, 4, 6 etc.. for(var i = 0; i < arr.length; i++) { if(arr[i] % 2 === 0) { sumPar += arr.length; } else { sumOdd += arr.length; } // Even numbers // Odd numbers document.getElementById("print").innerHTML = "Partall: " + sumPar + "<br />" + "Oddetall: " + sumOdd; } } } </script>

这是错误的地方，我不知道是什么.

Its something that is wrong here, and I dont know what.

推荐答案

您正在添加 arr.length ，它是数组的长度.相反，您应该简单地增加数字

You were adding arr.length which is the array length. Instead you should simply increment the number

var tall = [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]; liste(tall); function liste(arr) { var sumOdd = 0; var sumPar = 0; for (var i = 0; i < arr.length; i++) { if (arr[i] % 2 === 0) { sumPar++; } else { sumOdd++; } } console.log("Odd : " + sumOdd); console.log("Par : " + sumPar); }