NSURL总是返回Nil

本文介绍了NSURL总是返回Nil的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有WCF服务，我想从我的Web服务中获取数据.但是URL总是返回nil.为什么?我想向来自文本字段值的WCF发送参数.例如；

I have WCF service and I want to get data from my web service. But URL always returns nil. Why? I want to send parameter to WCF which comes from text field value. For example;

txtfield.text = @"ATAŞEHİR";

怎么了?

NSString *request = [NSString stringWithFormat:@"www.xxxxxxxx/CCWCF.svc/MethodName/%@",txtfield.text]; NSURL *URL = [NSURL URLWithString:[request stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding]];

我尝试了不同的方法，但结果没有改变.

I tried different things but result didn't change.

NSURL *URL = [NSURL URLWithString:[NSString stringWithFormat:@"www.xxxxxxxx/CCWCF.svc/MethodName/%@",txtfield.text]];

或:

NSURL *URL = [[NSURL alloc] initWithString:[request stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding]];

推荐答案

NSString* encodedText = [txtfield.text stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; NSString *request = [NSString stringWithFormat:@"www.xxxxxxxx/CCWCF.svc/MethodName/%@",encodedText]; NSURL *URL = [NSURL URLWithString:request];

另外， [NSString stringByAddingPercentEscapesUsingEncoding:] 对于URL编码可能会有些问题.使用 Core Foundation 有一种更安全的方法.参见 madebymany/blog/url-encoding-an-例如nsstring-on-ios (找不到SO问题).

On a separate note, [NSString stringByAddingPercentEscapesUsingEncoding:] can be a bit problematic for URL encoding. There is a safer way using Core Foundation. See madebymany/blog/url-encoding-an-nsstring-on-ios, for example (can't find the SO question).