本文介绍了查找列表元素之间的差异的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
给出一个数字列表,如何找到第(c0)个元素与其第(c1>)个元素之间的差异?
Given a list of numbers, how does one find differences between every (i)-th elements and its (i+1)-th?
使用lambda表达式还是列表理解更好?
Is it better to use a lambda expression or maybe a list comprehension?
例如:
给出列表t=[1,3,6,...],目标是找到列表v=[2,3,...],因为3-1=2,6-3=3等.
Given a list t=[1,3,6,...], the goal is to find a list v=[2,3,...] because 3-1=2, 6-3=3, etc.
推荐答案>>> t [1, 3, 6] >>> [j-i for i, j in zip(t[:-1], t[1:])] # or use itertools.izip in py2k [2, 3]
更多推荐
查找列表元素之间的差异
发布评论