序列化番石榴的不可变表

本文介绍了序列化番石榴的不可变表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用 Guava 的17.0版本，尤其是新的收藏类型.尝试通过Socket编写ImmutableTable时，我意识到该类及其具体实现似乎不可序列化.

I am using the version 17.0 of Guava, especially the new collection types. While trying to write an ImmutableTable through a Socket, I realized that the class and its concrete implementations do not seem to be serializable.

但是，以下两张票证似乎表明开发人员已意识到该问题:

However, the two following tickets seem to indicate that the developers are aware of the issue:

• 问题1264
• 问题1562

• Issue 1264
• Issue 1562

你们中有人对包含ImmutableTable属性的类进行序列化吗?我该怎么做，而又不使用Map的Map?

Do any of you serialize classes containing ImmutableTable attributes? How could I do this, without resorting to using a Map of Maps?

推荐答案

即使ImmuttableTable无法序列化，您也可以始终使用 HashBasedTable 或其他表实现.然后反序列化之后，使用ImmutableTable.copyOf(deserialized)再次获取ImmutableTable.不完全优雅，但实施起来很简单.

Even though ImmuttableTable isn't serializable, you could always use a HashBasedTable or one of the other Table implementations. And then after deserialization, use ImmutableTable.copyOf(deserialized) to get the ImmutableTable again. Not exactly elegant, but simple enough to implement.