通过反射创建 F# 记录

本文介绍了通过反射创建 F# 记录的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何使用反射在 F# 中创建记录类型?谢谢

How can I create a record type in F# by using reflection? Thanks

推荐答案

您可以使用 FSharpValue.MakeRecord[MSDN] 来创建记录实例，但我认为 F# 中没有任何用于定义记录类型的东西.但是，记录会编译为简单的类，因此您可以像在 C# 中一样构建一个类.TypeBuilder[MSDN] 可能是一个很好的起点.

You can use FSharpValue.MakeRecord[MSDN] to create a record instance, but I don't think there's anything baked into F# for defining record types. However, records compile to simple classes, so you could build a class as you would in C#. TypeBuilder[MSDN] may be a good starting point.

将 [] 添加到类型是使其成为记录所需的全部内容.下面是如何在运行时执行此操作的示例.

Adding [<CompilationMapping(SourceConstructFlags.RecordType)>] to the type is all that's required to make it a record. Here's an example of how to do this at run-time.

let asmName = AssemblyName("Foo") let asm = AppDomain.CurrentDomain.DefineDynamicAssembly(asmName, AssemblyBuilderAccess.RunAndCollect) let moduleBldr = asm.DefineDynamicModule("Test") let typeBldr = moduleBldr.DefineType("MyRecord", TypeAttributes.Public) let attrBldr = CustomAttributeBuilder( typeof<CompilationMappingAttribute>.GetConstructor([|typeof<SourceConstructFlags>|]), [|box SourceConstructFlags.RecordType|]) typeBldr.SetCustomAttribute(attrBldr) let typ = typeBldr.CreateType() printfn "%b" <| FSharpType.IsRecord(typ) //true