在变量中存储大量数字的正确方法

本文介绍了在变量中存储大量数字的正确方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想研究数字，但无论是基本数字，我一直在写斐波那契数列的算法和用于查找素数的蛮力路径！

I would like to play around with numbers and however elementary, Ive been writing algorithms for the fibonacci sequence and a brute force path for finding prime numbers!

我不是程序员，只是一个数学家.

Im not a programmer, just a math guy.

但是，我经常遇到一个安静的问题，就是长而长的双排和浮子经常没有空间.

However, a problem I run into quiet often is that a long long, double and floats often run out of room.

如果我想继续在JAVA中工作，可以用什么方式创建自己的数据类型，以免空间不足.

If I wanted to continue to work in JAVA, in what way can I create my own data type so that I dont run out of room.

从概念上讲，我想像这样将3个双打组合在一起，

Conceptually, I thought to put 3 doubles together like so,

public class run { static double a = 0; static double b = 0; //static double c = 0; static void bignumber(boolean x) { if (x == true && a < 999999999) { ++a; } else if (x == true && a == 999999999) { ++b; a = 0; } System.out.print(b + "." + a + " \n"); } public static void main(String[] args) { while(true) { bignumber(true); } } }

有没有更好的方法可以做到这一点，

is there a better way to do this,

我希望有一天能说

mydataType X = 18476997032117414743068356202001644030185493386634 10171471785774910651696711161249859337684305435744 58561606154457179405222971773252466096064694607124 96237204420222697567566873784275623895087646784409 33285157496578843415088475528298186726451339863364 93190808467199043187438128336350279547028265329780 29349161558118810498449083195195450098483937752272570 52578591944993870073695755688436933812779613089230 39256969525326162082367649031603655137144791393234 7169566988069

mydataType X = 18476997032117414743068356202001644030185493386634 10171471785774910651696711161249859337684305435744 58561606154457179405222971773252466096064694607124 96237204420222697567566873784275623895087646784409 33285157496578843415088475528298186726451339863364 93190808467199043187438128336350279547028265329780 29349161558118810498449083195450098483937752272570 52578591944993870073695755688436933812779613089230 39256969525326162082367649031603655137144791393234 7169566988069

或在此网站

我也尝试过

package main; import java.math.BigInteger; public class run { BigDecimal a = 184769970321174147430683562020019566988069; public static void main(String[] args) { } }

但是它似乎仍然超出范围

But it still seems to be out of range

推荐答案

为此目的使用BigDecimal(而不是double)和BigInteger(而不是int，long)，但是您只能通过他们的方法与他们合作.没有运算符，可以使用.

Use BigDecimal (instead of double), and BigInteger (instead of int, long) for that purpose, But you can only work with them by their methods. No operators, can be used.

像这样使用:

BigInteger big = new BigInteger("4019832895734985478385764387592") // Strings... big.add(new BigInteger("452872468924972568924762458767527");

与BigDecimal