iPhone发布到Django并获得CSRF验证失败

本文介绍了iPhone发布到Django并获得CSRF验证失败的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我发送一个POST请求从IPhone到Django，并得到CSRF验证失败，我不能完全理解。 我试图通过互联网找到一个很好的解决方案，但我不能。 有没有简单的方法来发送到django？

这是我的代码：

NSString * post = [NSString stringWithFormat：@s = aaa& r = k& c = gg]; NSData * postData = [post dataUsingEncoding：NSUTF8StringEncoding allowLossyConversion：YES]; NSString * postLength = [NSString stringWithFormat：@％d，[postData length]]; NSMutableURLRequest * request = [[NSMutableURLRequest alloc] init]; [请求setURL：[NSURL URLWithString：（@http：// localhost：8000 / messages / views /）]]; [request setHTTPMethod：@POST]; [request setValue：postLength forHTTPHeaderField：@Content-Length]; [request setValue：@application / x-www-form-urlencoded charset = utf-8forHTTPHeaderField：@Content-Type]; [请求setHTTPBody：postData]; NSError *错误; NSURLResponse * response; NSData * urlData = [NSURLConnection sendSynchronousRequest：request returnedResponse：& response error：& error]; NSString * data = [[NSString alloc] initWithData：urlData encoding：NSUTF8StringEncoding]; NSLog（data）;

解决方案

通常这归结为正确设置头。已经详细说明了答案。您需要的相关部分是：

xhr.setRequestHeader（X-CSRFToken，令牌）

有关从Cookie获取令牌的详细信息，请参阅链接的答案，为简洁起见，我没有将其从那里复制。我真的不知道你的代码的上下文，所以这种检索方法可能不会直接应用。无论如何，您需要以某种方式获取令牌。

当您拥有令牌时，请向 NSMutableURLRequest 中添加标题。发布请求时，错误应该已经没了。

[request addValue：token forHTTPHeaderField：@X-CSRFToken];

I send a POST request from IPhone to Django and get "CSRF verification failed", which I can't perfectly understand. I tried to find a good solution over the internet, but I couldn't . is there any simple way to POST to django?

this is my code:

NSString *post =[NSString stringWithFormat:@"s=aaa&r=k&c=gg"]; NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; [request setURL:[NSURL URLWithString:(@"localhost:8000/messages/views/")]]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSError *error; NSURLResponse *response; NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; NSString *data=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding]; NSLog(data);

解决方案

Normally this boils down to setting the headers correctly. There is an answer that already details this. The relevant part you need is this:

xhr.setRequestHeader("X-CSRFToken", token)

See the linked answer for details on getting the token from the cookies, for brevity I didn't copy it from there. I don't really know the context of your code, so this method of retrieval might not directly apply. Regardless, you need to get the token somehow.

When you have the token, add a header to the NSMutableURLRequest. Upon posting the request, the error should be gone.

[request addValue:token forHTTPHeaderField:@"X-CSRFToken"];