本文介绍了如何在SQL中获取表的倒数第二行而不使用“ORDER BY”的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在接受采访时被问到一个问题:
I have been asked a question in an interview :
How to get second last record of a SQL table ?...WITHOUT USING "ORDER BY" , and assuming there is no identity column推荐答案
嗨kiran, 如果您在表格中使用身份,则以下查询将非常有用, Hi kiran, If you are using an identity in your table , following query will be useful, select * from gallery where GalleryItemid=(ident_current('gallery')-1)
我希望它可以帮助你。
I hope it helps you.
我找到了一个解决方案,但是有一个小的限制,但它可以在99%的情况下工作.. i found a solution but there is a small limitation, however it will work in 99% cases.. select top 1* from ( select * from [TableName] EXCEPT select top (select (COUNT(1)-2) from [TableName]) * from [TableName]) A
限制:如果最后一行/秒的最后一行是任何行的副本,那么它将给出错误的结果......但在实际情况下这种情况非常罕见。
Limitation : If last 2 rows/ second last row is duplicate of any row then it will give wrong result... but such cases are very rare in real scenarios.
select * from emp where empid not in ( select top ( (select count(*) from emp) - 2 ) empid from emp )
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如何在SQL中获取表的倒数第二行而不使用“ORDER BY”
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