jdbc ResultSet已关闭

编程入门 行业动态 更新时间:2024-10-22 09:33:14
本文介绍了jdbc ResultSet已关闭的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

我有以下来源。

在insertMessage(..)中,它调用selectMessage来检查是否存在重复记录。

In insertMessage(..), it calls selectMessage to check whether duplicate record exists or not.

但是会发生此错误。 在我的大脑中,它运行正常,因为datasource给了我新的连接......也许

But this error occurs. In my brain, it works fine because datasource gives me new Connection...maybe

java.sql.SQLException: ResultSet closed at org.sqlite.RS.checkOpen(RS.java:63) at org.sqlite.RS.findColumn(RS.java:108) at org.sqlite.RS.getString(RS.java:317) at org.apachemons.dbcp.DelegatingResultSet.getString(DelegatingResultSet.java:263) at org.apachemons.dbcp.DelegatingResultSet.getString(DelegatingResultSet.java:263) at org.springframework.context.support.CachedMessageSourceDao.selectMessage(CachedMessageSourceDao.java:68) at org.springframework.context.support.CachedMessageSourceDao.insertMessage(CachedMessageSourceDao.java:94) at MessageSourceDemo.main(MessageSourceDemo.java:11)

public String selectMessage(String code, String language) { Connection conn = null; PreparedStatement pstmt = null; ResultSet rs = null; String value = null; String sql = "SELECT code, value, language FROM " + TABLE + " where code=? and language=? and flag = '" + FLAG_OK + "'"; try { conn = dataSource.getConnection(); conn.setAutoCommit(true); pstmt = conn.prepareStatement(sql); pstmt.setString(1, code); pstmt.setString(2, language); rs = pstmt.executeQuery(); rs.next(); String _code = rs.getString("code"); String _value = rs.getString("value"); String _language = rs.getString("language"); Locale _locale = new Locale(_language); value = _value; } catch(SQLException ex) { ex.printStackTrace(); } finally { try { if(rs != null); if(pstmt != null) pstmt.close(); if(conn != null) conn.close(); } catch (SQLException e) { e.printStackTrace(); } } return value; } public synchronized void insertMessage(String code, String value, String language) throws SQLException { //Duplicate Message Check **if(selectMessage(code, language) != null) throw new SQLException("Duplicate message exists for code: " + code + " and" + "language: " + language);** String sql = "INSERT INTO " + TABLE + " (code, value, language, flag) values (?, ?, ?, '" + FLAG_OK + "')"; Connection conn = null; PreparedStatement pstmt = null; try { conn = dataSource.getConnection(); conn.setAutoCommit(true); pstmt = conn.prepareStatement(sql); pstmt.setString(1, code); pstmt.setString(2, value); pstmt.setString(3, language); pstmt.execute(); } catch(SQLException ex) { ex.printStackTrace(); } finally { try { if(pstmt != null) pstmt.close(); if(conn != null) conn.close(); } catch (SQLException e) { e.printStackTrace(); } } notifyMessageChange(); //Realtime apply to MessageSource }

推荐答案

您的结果集可能没有任何记录,这就是 next()关闭它的原因。

Your resultset probably didn't have any record, which is the reason why next() closed it.

next()返回一个布尔值,检查它。

next() returns a boolean, check it.

更多推荐

jdbc ResultSet已关闭

本文发布于:2023-10-18 10:55:59,感谢您对本站的认可!
本文链接:https://www.elefans.com/category/jswz/34/1504029.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
本文标签:jdbc   ResultSet

发布评论

评论列表 (有 0 条评论)
草根站长

>www.elefans.com

编程频道|电子爱好者 - 技术资讯及电子产品介绍!