如果在python中出现条件，如何避免多个单位?

本文介绍了如果在python中出现条件，如何避免多个单位?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

考虑代码段:

def check_conditions(range_of_numbers): #method returns a list containing messages list1 = [] if condition1: list1.append("message1") if condition2: list1.append("message2") if condition3: list1.append("message3") try: for i in range_of_numbers: int(i) except ValueError: list1.append("message4") return message

仅当满足条件时，我才希望在with消息中有一个列表.我不使用多个if，因为它增加了代码的复杂性，并且每次添加新参数时，我最终都会添加新的if条件.

I want to have a list in the with messages only if the conditions were satisfied. I do not use multiple if's since it adds on to the code complexity and every time a new parameter is added I would end up adding a new if condition.

推荐答案

仅对条件/消息对进行循环:

just loop on the condition/message couples for instance:

for condition,message in ((condition1,"message1"),(condition2,"message2"),(condition3,"message3")): if condition: list1.append(message)

如果条件是排他性的，请考虑在一个条件匹配的情况下添加break.

if the conditions are exclusive, consider adding a break if one condition matches.

列表理解版本(虽然更"pythonic"，但在首次条件匹配时无法中断):

list comprehension version (more "pythonic" but not possible to break on first condition match, though):

list1 = [message for condition,message in ((condition1,"message1"),(condition2,"message2"),(condition3,"message3")) if condition]