本文介绍了删除列的方式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想使用dplyr> = 0.7删除列向量
I would like to remove a vector of columns using dplyr >= 0.7
library(dplyr) data(mtcars) rem_cols <- c("wt", "qsec", "vs", "am", "gear", "carb") head(select(mtcars, !!paste0("-", rem_cols)))
错误:字符串必须与列名匹配.未知列:-wt,-qsec,-vs,-am,-gear,-carb
Error: Strings must match column names. Unknown columns: -wt, -qsec, -vs, -am, -gear, -carb
dplyr< 0.7的工作方式如下:
dplyr < 0.7 worked as follows:
head(select_(mtcars, .dots = paste0("-", rem_cols))) # mpg cyl disp hp drat # Mazda RX4 21.0 6 160 110 3.90 # Mazda RX4 Wag 21.0 6 160 110 3.90 # Datsun 710 22.8 4 108 93 3.85 # Hornet 4 Drive 21.4 6 258 110 3.08 # Hornet Sportabout 18.7 8 360 175 3.15 # Valiant 18.1 6 225 105 2.76我已经尝试过rlang:syms(),!!,!!!,quo和enquo的所有组合,可以想到...帮助!?
I've tried about all combinations of rlang:syms(), !!, !!!, quo and enquo that I can think of... help!?
推荐答案我们可以使用one_of
mtcars %>% select(-one_of(rem_cols))更多推荐
删除列的方式
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