重命名列表项

本文介绍了重命名列表项的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有以下列表listaValores

listaValores <- c() for(valores in 1:numRepeticion){ listaValores <- c(listaValores, readWorksheetFromFile(file = file.read, sheet = sheet.read, startRow = startRow.read+(12*(valores-1)), startCol = startCol.read[i], endRow = startRow.read+((12*valores)-1) , endCol = startCol.read[i], header = FALSE)) }

返回:

$Col1 [1] 32824 35646 34650 29328 27376 28548 35363 34740 49181 57960 55550 50626 $Col1 [1] 52610 55085 58576 51300 50968 58104 56585 38273 54216 59043 67487 58067 $Col1 [1] 59142 68593 77510 73434 83545 83483 79635 69269 85703 73080

如何将其元素重命名为2014，2015，2016?

How to renames it's elements to 2014, 2015, 2016?

推荐答案

请注意，您有list.因此，您没有colnames，而是names.您可以像这样编辑它们:

Note that you have a list. Therefore, you do not have colnames but names. You can edit them like this:

l <- list(col1 = c(123123, 12123, 123123), col1 = c(123123, 12123, 123123)) l # $col1 # [1] 123123 12123 123123 # # $col1 # [1] 123123 12123 123123 names(l) # [1] "col1" "col1" names(l) <- c("2014", "2015") l # $`2014` # [1] 123123 12123 123123 # # $`2015` # [1] 123123 12123 123123

要仅编辑列表中的某些条目，请指定索引:

To only edit certain entries in the list, specify an index:

names(l)[1] <- "new_name" l # $`new_name` # [1] 123123 12123 123123 # # $`2015` # [1] 123123 12123 123123

如果您想进一步了解R中的不同数据类型，我可以推荐哈德利·威克姆(Hadley Wickham)的摘要.

If you'd like to know more about the different data types in R, I can recommend Hadley Wickham's summary.