如何求和下一行的总和,直到达到阈值并再次重置计数器。
How do I sum distance over next row until threshold point is reached and reset the counter again.
例如,如果阈值为10,我试图获得以下输出:
For instance if the threshold value is 10 I am trying to get the following output:
1 | 2019-04-09 00:00:00 | 2 1 | 2019-04-09 00:00:30 | 7 (2 + 5) 1 | 2019-04-09 00:01:00 | 10 ( 7 + 3 ) 1 | 2019-04-09 00:01:45 | 7 RESET 1 | 2019-04-09 00:02:30 | 13 (7 + 6 ) 1 | 2019-04-09 00:03:00 | 1 RESET但是我所能实现的是通过以下查询获取累积距离:
But all I could achieve is get cumulative distance with following query:
SELECT *,总和(距离)超过(按日期升序排列)为running_distance FROM表;
我正在使用PostgreSQL。
I am using PostgreSQL.
推荐答案使用用户定义的聚合
实时测试: sqlfiddle/#!17/16716/2
SELECT *, sum_with_reset(distance, 10) over (order by date asc) as running_distance FROM tbl;用户定义的汇总sum_with_reset定义:
create or replace function sum_reset_accum( _accumulated numeric, _current numeric, _threshold numeric ) returns numeric as $$ select case when _accumulated >= _threshold then _current else _current + _accumulated end $$ language sql; create aggregate sum_with_reset(numeric, numeric) ( sfunc = sum_reset_accum, stype = numeric, initcond = 0 );数据
CREATE TABLE tbl ("user_id" int, "date" timestamp, "distance" int) ; INSERT INTO tbl ("user_id", "date", "distance") VALUES (1, '2019-04-09 00:00:00', 2), (1, '2019-04-09 00:00:30', 5), (1, '2019-04-09 00:01:00', 3), (1, '2019-04-09 00:01:45', 7), (1, '2019-04-09 00:02:30', 6), (1, '2019-04-09 00:03:00', 1) ;输出:
| user_id | date | distance | running_distance | |---------|----------------------|----------|------------------| | 1 | 2019-04-09T00:00:00Z | 2 | 2 | | 1 | 2019-04-09T00:00:30Z | 5 | 7 | | 1 | 2019-04-09T00:01:00Z | 3 | 10 | | 1 | 2019-04-09T00:01:45Z | 7 | 7 | | 1 | 2019-04-09T00:02:30Z | 6 | 13 | | 1 | 2019-04-09T00:03:00Z | 1 | 1 |单线:
create or replace function sum_reset_accum( _accumulated numeric, _current numeric, _threshold numeric ) returns numeric as $$ select _current + _accumulated * (_accumulated < _threshold)::int $$ language 'sql';Postgres布尔值可以使用强制转换运算符将true转换为1,将false转换为0 :: int 。
Postgres boolean can cast true to 1, false to 0 by using cast operator ::int.
您也可以使用 plpgsql 语言:
create or replace function sum_reset_accum( _accumulated numeric, _current numeric, _threshold numeric ) returns numeric as $$begin return _current + _accumulated * (_accumulated < _threshold)::int; end$$ language 'plpgsql';请注意,您无法在sqlfiddle上创建plpgsql函数,因此无法在sqlfiddle上测试该plpgsql代码。您可以在自己的机器上。
Note that you cannot create plpgsql function on sqlfiddle, so you cannot test that plpgsql code on sqlfiddle. You can, on your machine though.
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求和,直到达到阈值,然后重置计数器
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