Bash脚本在出现错误时重新启动程序

本文介绍了Bash脚本在出现错误时重新启动程序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在linux(我使用Ubuntu)中，我运行了一个(红宝石)程序，该程序整天连续运行.我的工作是监视程序是否失败，如果失败，请重新启动程序.只需按一下"Up"作为上一个命令，然后按"Enter"即可.很简单.

In linux (I use a Ubuntu), I run a (ruby) program that continually runs all day long. My job is to monitor to see if the program fails and if so, re-launch the program. This consists up simply hitting 'Up' for last command and 'Enter'. Simple enough.

必须有一种方法可以编写bash脚本来监视程序是否停止运行并自动重新启动.

There has to be a way to write a bash script to monitor my program if its stops working and to re-launch it automatically.

我该怎么做?

奖励是能够在程序出错时保存程序的输出.

A bonus is to be able to save the output of the program when it errors.

推荐答案

您可以做什么:

#!/bin/bash LOGFILE="some_file.log" LAUNCH="your_program" while : do echo "New launch at `date`" >> "${LOGFILE}" ${LAUNCH} >> "${LOGFILE}" 2>&1 & wait done

另一种方法是定期检查PID:

Another way is to periodicaly check the PID:

#!/bin/bash LOGFILE="some_file.log" LAUNCH="your_program" PID="" CHECK="" while : do if [ -n "${PID}" ]; then CHECK=`ps -o pid:1= -p "${PID}"` fi # If PID does not exist anymore, launch again if [ -z "${CHECK}" ]; then echo "New launch at `date`" >> "${LOGFILE}" # Launch command and keep track of the PID ${LAUNCH} >> "${LOGFILE}" 2>&1 & PID=$! fi sleep 2 done