在 Python 中删除小数点后的尾随零

本文介绍了在 Python 中删除小数点后的尾随零的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我使用的是 Python 2.7.我需要在末尾替换 "0" 字符串.

比如说，a = "2.50":

a = a.replace('0', '')

我得到 a = 2.5，我对这个结果没问题.

现在 a = "200":

a = a.replace('0', '')

我得到 a = 2，这个输出是我同意的设计.但我希望输出 a = 200.

其实我看的是

当末尾小数点后的任何值是"0"时替换那个"0"没有值.

以下是示例，我期待结果.

IN: a = "200"输出:a = 200在:a =150"输出:a = 150在:a = 2.50输出:a = 2.5在:a =1500"出:a = 1500在:a =1500.80"输出:a = 1500.8在:a =1000.50"输出:a = 1000.5

不是一个值是字符串.

注意:有时 a = 100LL 或 a = 100.50mt.

解决方案

您可以使用正则表达式来做到这一点:

导入重新rgx = repile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])')b = rgx.sub('\2',a)

其中b是从a中去除小数点后的尾零的结果.

我们可以把它写成一个很好的函数:

导入重新tail_dot_rgx = repile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])')def remove_tail_dot_zeros(a):返回tail_dot_rgx.sub(r'\2',a)

现在我们可以测试一下:

>>>remove_tail_dot_zeros('2.00')'2'>>>remove_tail_dot_zeros('200')'200'>>>remove_tail_dot_zeros('150')'150'>>>remove_tail_dot_zeros('2.59')'2.59'>>>remove_tail_dot_zeros('2.50')'2.5'>>>remove_tail_dot_zeros('2.500')'2.5'>>>remove_tail_dot_zeros('2.000')'2'>>>remove_tail_dot_zeros('2.0001')'2.0001'>>>remove_tail_dot_zeros('1500')'1500'>>>remove_tail_dot_zeros('1500.80')'1500.8'>>>remove_tail_dot_zeros('1000.50')'1000.5'>>>remove_tail_dot_zeros('200.50mt')'200.5 公吨'>>>remove_tail_dot_zeros('200.00mt')'200 吨'

I am using Python 2.7. I need to replace "0" string at the end.

Say, a = "2.50":

a = a.replace('0', '')

I get a = 2.5, and I am fine with this result.

Now a = "200":

a = a.replace('0', '')

I get a = 2, and this output is as per design I agreed. But I expect the output a = 200.

Actually what I am looking is

when any value after decimal point at the end is "0" replace that "0" with None value.

Below are the examples and I am expecting results.

IN: a = "200" Out: a = 200 In: a = "150" Out: a = 150 In: a = 2.50 Out: a = 2.5 In: a = "1500" Out: a = 1500 In: a = "1500.80" Out: a = 1500.8 In: a = "1000.50" Out: a = 1000.5

Not a value is string.

Note: sometimes a = 100LL or a = 100.50mt.

解决方案

You can do this using a regular expression:

import re rgx = repile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])') b = rgx.sub('\2',a)

Where b is the result of removing tailing zeros after the decimal point from a.

We can write this in a nice function:

import re tail_dot_rgx = repile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])') def remove_tail_dot_zeros(a): return tail_dot_rgx.sub(r'\2',a)

And now we can test this:

>>> remove_tail_dot_zeros('2.00') '2' >>> remove_tail_dot_zeros('200') '200' >>> remove_tail_dot_zeros('150') '150' >>> remove_tail_dot_zeros('2.59') '2.59' >>> remove_tail_dot_zeros('2.50') '2.5' >>> remove_tail_dot_zeros('2.500') '2.5' >>> remove_tail_dot_zeros('2.000') '2' >>> remove_tail_dot_zeros('2.0001') '2.0001' >>> remove_tail_dot_zeros('1500') '1500' >>> remove_tail_dot_zeros('1500.80') '1500.8' >>> remove_tail_dot_zeros('1000.50') '1000.5' >>> remove_tail_dot_zeros('200.50mt') '200.5mt' >>> remove_tail_dot_zeros('200.00mt') '200mt'