检查字符串在PHP中是否以数字结尾

本文介绍了检查字符串在PHP中是否以数字结尾的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试实现以下功能.最好在这里使用某种类型的正则表达式吗?我也需要捕获这个数字.

I'm trying to implement the function below. Would it be best to use some type of regex here? I need to capture the number too.

function endsWithNumber($string) { $endsWithNumber = false; // Logic return $endsWithNumber; }

推荐答案

$test="abc123"; //$test="abc123n"; $r = preg_match_all("/.*?(\d+)$/", $test, $matches); //echo $r; //print_r($matches); if($r>0) { echo $matches[count($matches)-1][0]; }

正则表达式的解释如下:

the regex is explained as follows:

.*? -这将从开始就占据字符串中的所有字符，直到找到下一部分的匹配项为止.

.*? - this will take up all the characters in the string from the start up until a match for the subsequent part is also found.

(\ d +)$-这是一个或多个数字，直到字符串的末尾分组为止.

(\d+)$ - this is one or more digits up until the end of the string, grouped.

没有?在第一部分中，只有最后一位数字将在第二部分中匹配，因为之前的所有数字都将由.*

without the ? in the first part, only the last digit will be matched in the second part because all digits before it would be taken up by the .*