子查询返回每个父 ID 的最新条目

本文介绍了子查询返回每个父 ID 的最新条目的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个包含文档条目的父表，并且我有一个历史表，每次用户访问其中一个文档时都会记录一个审计条目.

I have a parent table with entries for documents and I have a history table which logs an audit entry every time a user accesses one of the documents.

我正在编写一个搜索查询来返回一个文档列表(按各种标准过滤)，其中包含最新的用户 ID，以访问结果集中返回的每个文档.

I'm writing a search query to return a list of documents (filtered by various criteria) with the latest user id to access each document returned in the result set.

因此对于

DOCUMENTS ID | NAME 1 | Document 1 2 | Document 2 3 | Document 3 4 | Document 4 5 | Document 5 HISTORY DOC_ID | USER_ID | TIMESTAMP 1 | 12345 | TODAY 1 | 11111 | IN THE PAST 1 | 11111 | IN THE PAST 1 | 12345 | IN THE PAST 2 | 11111 | TODAY 2 | 12345 | IN THE PAST 3 | 12345 | IN THE PAST

我希望从我的搜索中获得回报，例如

I'd be looking to get a return from my search like

ID | NAME | LAST_USER_ID 1 | Document 1 | 12345 2 | Document 2 | 11111 3 | Document 3 | 12345 4 | Document 4 | 5 | Document 5 |

我可以通过一个 SQL 查询和两个表之间的连接轻松地做到这一点吗?

Can I easily do this with one SQL query and a join between the two tables?

推荐答案

修改 Andy White 生成的内容，并将方括号(MS SQL Server 表示法)替换为 DB2(和 ISO 标准 SQL)分隔标识符":

Revising what Andy White produced, and replacing square brackets (MS SQL Server notation) with DB2 (and ISO standard SQL) "delimited identifiers":

SELECT d.id, d.name, h.last_user_id FROM Documents d LEFT JOIN (SELECT r.doc_id AS id, user_id AS last_user_id FROM History r JOIN (SELECT doc_id, MAX("timestamp") AS "timestamp" FROM History GROUP BY doc_id ) AS l ON r."timestamp" = l."timestamp" AND r.doc_id = l.doc_id ) AS h ON d.id = h.id

我不确定timestamp"或TIMESTAMP"是否正确——可能是后者.

I'm not absolutely sure whether "timestamp" or "TIMESTAMP" is correct - probably the latter.

这样做的好处是它将 Andy 版本中的内部相关子查询替换为更简单的非相关子查询，这有可能(从根本上?)更高效.

The advantage of this is that it replaces the inner correlated sub-query in Andy's version with a simpler non-correlated sub-query, which has the potential to be (radically?) more efficient.