有人可以帮忙吗？

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我是新的C程序学生。我想我们是否可以在C中编写一个只触发其功能来执行某项操作的程序？在这种情况下，我有一个程序，但它不工作。我想要的是打印Hello的功能。没有向函数传递值。编写程序的正确方法是什么？ #include< stdio.h> 无效计算; / *函数原型* / int main（） {计算; / *函数调用* / 返回0; } 无效计算 { printf（你好）; 返回; } 谢谢 Tim

解决方案

----- BEGIN PGP签名消息----- 哈希：SHA1 Tiny Tim写道：

我是新的C程序学生。我想知道我们能不能在C中编写一个程序只是触发它的功能才能执行某个操作？在这种情况下，我有一个程序但它不起作用。我想要的是用于打印Hello的功能。没有向函数传递值。编写程序的正确方法是什么？ #include< stdio.h> 无效计算; / *函数原型* /

Nope。这不是函数原型。然而，无效计算（无效）; 是函数原型。注意区别？一个函数（原型与否）有一个零/ 或更多参数的列表，并通过跟踪括号参数列表指定为函数。 />

int main（） {计算; / *函数调用* /

不。那不是函数调用。充其量（Compute没有被声明为无效的），这将是一个涉及单个变量的表达式。如果你想要一个函数调用，你应该编码 Compute（）;

return 0; } void计算

需要零个或多个参数的参数列表应该是 void Compute（）/ *或者void void Compute（void）* /

{ printf（" Hello"）; 返回; } 谢谢 Tim

HTH - - Lew Pitcher -----开始PGP签名----- 版本：GnuPG v1.4.3（MingW32） - WinPT 0.11.12 iD8DBQFE4zjNagVFX4UWr64RAuR2AJ9YfRph / ZbwBG8nH7qOziTqddV8JQCfXMte n20INoD8 + uggOY5YzXzwdWA = = + C8Q -----结束PGP签名-----

Tiny Tim< ; ts ***** @ streamyxwrote：

[ - text / plain，encoding quoted-printable，charset：iso-8859-1,25行 - ]

如果可以提供帮助，请不要发表编码文章。

#include< stdio.h>

void Compute; / *函数原型* /

void Compute（）; / *注意括号* /

int main（） { 计算; / *函数调用* /

Compute（）; / *再次* /

返回0; } void计算 void Compute（）/ *再次* /

{ printf（" Hello" ）; 返回; }

我建议购买一本C书，最好是 C编程语言，尽快。 - C. Benson Manica |我*应该*知道我在说什么 - 如果我 cbmanica（at）gmail |不，我需要知道。火焰欢迎。

>

Nope。那不是函数调用。充其量（Compute没有被声明为无效的），这将是一个涉及单个变量的表达式。如果你想要一个函数调用，你应该编码计算（）; - - Lew Pitcher

谢谢Lew Pitcher先生这样的超级回复。我遇到了问题已经解决了。现在我可以继续前进了。再次感谢 Rgds， Tim

I am new C program student. I wonder can we write a program in C that just trigger its function to do a certain action ? In this case, I have a program but it is not working. What I want is for the function to print "Hello". No passing of values to or from the function. What is the correct way to write the program? #include <stdio.h> void Compute ; /*function prototype*/ int main () { Compute; /*function call*/ return 0 ; } void Compute { printf ("Hello"); return ; } Thank you Tim

解决方案

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Tiny Tim wrote:

I am new C program student. I wonder can we write a program in C that just trigger its function to do a certain action ? In this case, I have a program but it is not working. What I want is for the function to print "Hello". No passing of values to or from the function. What is the correct way to write the program? #include <stdio.h> void Compute ; /*function prototype*/

Nope. That''s not a function prototype. However, void Compute(void); is a function prototype. Notice the difference? A function (prototype or not) has a list of zero or more parameters, and is designated as a function by the presence of the trailing bracketed parameter list.

int main () { Compute; /*function call*/

Nope. That''s not a function call. At best (had Compute not been declared as void), that would be an expression involving a single variable. If you wanted a function call, you should have coded Compute();

return 0 ; } void Compute

Requires a parameter list of zero or more parameters Should have been void Compute() /* or perhaps void Compute(void) */

{ printf ("Hello"); return ; } Thank you Tim

HTH - -- Lew Pitcher -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.3 (MingW32) - WinPT 0.11.12 iD8DBQFE4zjNagVFX4UWr64RAuR2AJ9YfRph/ZbwBG8nH7qOziTqddV8JQCfXMte n20INoD8+uggOY5YzXzwdWA= =+C8Q -----END PGP SIGNATURE-----

Tiny Tim <ts*****@streamyxwrote:

[-- text/plain, encoding quoted-printable, charset: iso-8859-1, 25 lines --]

Please don''t post encoded articles, if you can help it.

#include <stdio.h>

void Compute ; /*function prototype*/

void Compute(); /* note parentheses */

int main () { Compute; /*function call*/

Compute(); /* again */

return 0 ; } void Compute

void Compute() /* and again */

{ printf ("Hello"); return ; }

I''d advise procuring a C book, preferably "The C Programming Language", as soon as possible. -- C. Benson Manica | I *should* know what I''m talking about - if I cbmanica(at)gmail | don''t, I need to know. Flames welcome.

>

Nope. That''s not a function call. At best (had Compute not been declared as void), that would be an expression involving a single variable. If you wanted a function call, you should have coded Compute(); - -- Lew Pitcher

Thank you Mr. Lew Pitcher for such a superspeed reply. I got my problem solved already. Now I can move on. Thanks again Rgds, Tim

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