所有其他网址( / api / * 旁边)将直接投放,无代理。
如何使用node.js + express.js实现这一点?你可以给出一个简单的代码示例吗?
(我的控制下,Web服务器和远程 3000 服务器,两个运行node.js与express.js)
到目前为止,我发现这个 github/nodejitsu/node-http-proxy/ ,但阅读文档没有我更聪明我结束了
var proxy = new httpProxy.RoutingProxy(); app.all(/ api / *,function(req,res){ console.log(old request url+ req.url) req.url ='/ '+ req.url.split('/')。slice(2).join('/'); //删除'/ api'部分 console.log(new request url+ req。 url) proxy.proxyRequest(req,res,{ host:other_domain, port:3000 }); });但没有任何内容返回给原始的Web服务器(或最终用户),所以没有运气。
解决方案你想使用 http.request 创建类似的请求到远程API并返回其响应。
这样的东西:
var http = require('http'); / *您的应用程序配置在这里* / app.post('/ api / BLABLA',function(req,res){ var options = { // host to forward to host:'www.google', // port to forward to port:80, // path to forward to path:'/ api / BLABLA', // request method method:'POST', // header to send 标题:req.headers }; var creq = http.request(options,function(cres){ // set encoding cres .setEncoding('utf8'); //等待数据 cres.on('data',function(chunk){ res.write(chunk); }); cres.on('close',function(){ //关闭,让我们结束客户端请求以及 res.writeHead(cres。 statusCode); res.end(); }); cres.on('end',function(){ //完成,客户请求以及 res .writeHead(cres.statusCode); res.end(); }); })。on('error',function(e){ //我们收到错误,返回500错误给客户端和日志错误 console.log .message); res.writeHead(500); res.end(); }); creq.end(); });注意:我没有真正尝试过上述内容,所以可能会包含解析错误这将给你一个如何让它上班的提示。
To avoid same-domain AJAX issues, I want my node.js web server to forward all requests from URL /api/BLABLA to another server, for example other_domain:3000/BLABLA, and return to user the same thing that this remote server returned, transparently.
All other URLs (beside /api/*) are to be served directly, no proxying.
How do I achieve this with node.js + express.js? Can you give a simple code example?
(both the web server and the remote 3000 server are under my control, both running node.js with express.js)
So far I found this github/nodejitsu/node-http-proxy/ , but reading the documentation there didn't make me any wiser. I ended up with
var proxy = new httpProxy.RoutingProxy(); app.all("/api/*", function(req, res) { console.log("old request url " + req.url) req.url = '/' + req.url.split('/').slice(2).join('/'); // remove the '/api' part console.log("new request url " + req.url) proxy.proxyRequest(req, res, { host: "other_domain", port: 3000 }); });but nothing is returned to the original web server (or to the end user), so no luck.
解决方案You want to use http.request to create a similar request to the remote API and return its response.
Something like this:
var http = require('http'); /* your app config here */ app.post('/api/BLABLA', function(req, res) { var options = { // host to forward to host: 'www.google', // port to forward to port: 80, // path to forward to path: '/api/BLABLA', // request method method: 'POST', // headers to send headers: req.headers }; var creq = http.request(options, function(cres) { // set encoding cres.setEncoding('utf8'); // wait for data cres.on('data', function(chunk){ res.write(chunk); }); cres.on('close', function(){ // closed, let's end client request as well res.writeHead(cres.statusCode); res.end(); }); cres.on('end', function(){ // finished, let's finish client request as well res.writeHead(cres.statusCode); res.end(); }); }).on('error', function(e) { // we got an error, return 500 error to client and log error console.log(e.message); res.writeHead(500); res.end(); }); creq.end(); });Notice: I haven't really tried the above, so it might contain parse errors hopefully this will give you a hint as to how to get it to work.
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