在iOS中发送HTTP PATCH请求（Objective

本文介绍了在iOS中发送HTTP PATCH请求（Objective-c）的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用REST API，其中一个api是 PATCH ，我试图使用以下代码调用它，但它会抛出错误，而同样的api在 Postman client。

I am consuming REST APIs, one of the api is PATCH, i tried to invoke it using following code but it throws error, while same api works in Postman client.

+ (NSURLSessionTask *)callPATCHAPIWithAPIName:(NSString *)apiName andCompletionHandler:(void(^)(id result, NSInteger responseCode, NSError *error))completionHandler { NSString *getURL = @"192.168.1.100/UpdateDeviceInfo/iPhone6/OS 9.2"; NSURL *URL = [NSURL URLWithString:getURL]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:URL]; NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration]; sessionConfiguration.timeoutIntervalForRequest = 45.0f; NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration]; // Create Data from request NSData *requestData = [NSData dataWithBytes: [@"" UTF8String] length:[@"" length]]; [request setHTTPMethod:@"PATCH"]; [request setValue:[NSString stringWithFormat:@"%lu", (unsigned long)[requestData length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:requestData]; NSURLSessionDataTask *task = [session dataTaskWithRequest:request completionHandler: ^(NSData *data, NSURLResponse *response, NSError *error) { NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *) response; NSInteger responseCode = [httpResponse statusCode]; NSLog(@"response Code : %ld",(long)responseCode); }]; [task resume]; return task; }

[错误：错误Domain = NSURLErrorDomain Code = -1002不支持的URLUserInfo = {NSLocalizedDescription =不支持的URL，NSUnderlyingError = 0x14e86d490 {错误域= kCFErrorDomainCFNetwork代码= -1002（null）}}]

[Error :Error Domain=NSURLErrorDomain Code=-1002 "unsupported URL" UserInfo={NSLocalizedDescription=unsupported URL, NSUnderlyingError=0x14e86d490 {Error Domain=kCFErrorDomainCFNetwork Code=-1002 "(null)"}}]

我在查询字符串中传递参数，而不是在请求正文中。虽然同样的事情是在 Postman 客户端& Android。

I am passing parameters in query string, not in request body. Though same thing is working in Postman client & Android.

推荐答案

好像你在 NSString中有一个空格* getURL = @192.168.1.100 / UpdateDeviceInfo / iPhone6 / OS 9.2

我不相信网址格式支持空格！相反，如果需要空格，请确保使用 getURL = [getURL stringByAddingPercentEscapesUsingEncoding：NSUTF8StringEncoding]; 以便处理url字符串中的空格！

I do not believe whitespaces are supported in url formats! Instead, if whitespaces are necessary, make sure you use getURL = [getURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; in order to handle whitespaces in url strings!