如何传递一个类方法作为另一个函数的参数在C ++和OpenGL？

本文介绍了如何传递一个类方法作为另一个函数的参数在C ++和OpenGL？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我知道这个事情是有效的：

I know this thing works:

void myDisplay() { ... } int main() { ... glutDisplayFunc(myDisplay) ... }

所以我试图将myDisplay（）函数包含在一个类中。因为我想在将来用不同的类重载它。但是，编译器抱怨说，类型为'void（ClassBlah ::）（）'的参数不匹配'void（*）（）'的参数，

so I tried to include myDisplay() function to a class that I made. Because I want to overload it in the future with a different class. However, the compiler complains that

'。

这是我尝试做的：

class ClassBlah { .... void myDisplay() .... } ...... int main() { ... ClassBlah blah glutDisplayFunc(blah.myDisplay) ... }

有人知道如何解决这个问题吗？非常感谢。

Does anybody knows how to fix this problem? Many thanks.

推荐答案

首先，在非静态成员函数中有一个隐含的this指针，将 ClassBlah 中的 void myDisplay（）更改为静态。解决这个限制是很尴尬的，这就是为什么C ++ faq lite说不要这样做

Firstly, there is an implicit "this" pointer in non-static member functions, so you'll need to change your void myDisplay() in ClassBlah to be static. It's awkward to work around this limitation, which is why the C++ faq lite says don't do it

然后，您应该能够传递 ClassBlah :: myDisplay 。

Then, you should be able to pass the functions as ClassBlah::myDisplay.

根据您的重载动机（例如，您是否要在运行时或在编译时间执行热交换实现），您可以考虑使用实用程序handler静态类，它包含一个指向你的基类的指针，并通过该类指定责任。

Depending on your motivation for overloading (ie are you going to hotswap implementations in and out at runtime, or only at compile time?) you might consider a utility "handler" static class that contains a pointer to your base class, and delegates responsibility through that.