运行一个简单的后台任务的最简洁方法?

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我已经看到了至少五个模式，通过这些模式，您可以在工作线程中运行一些代码.最简单的:

I've seen at least five patterns through which you can have some code to run in a worker thread. Most simple:

new Thread(new Runnable() { public void run() { // } }).start();

我们可以扩展AsyncTask;我们有AsyncTaskLoader和其他Loader用于数据，Service等等.

We can extend AsyncTask; we have AsyncTaskLoader and other Loaders for data, Services and so on.

我认为这些优点中的每一个都有一些优点，这些优点我不在这里讨论.我想知道的是:哪种是运行简单动作的最合适，最简洁的方法?

I assume each one of those has some advantages which I'm not discussing here. What I'm wondering is: which is the most appropriate, concise way to run a simple action?

定义简单:

• 很短的动作，<1s;
• 无需处理UI元素；
• 单行命令或类似命令，因此用新类扩展AsyncTask似乎不合适；
• 在Activity或Fragment中无需通知任务成功；
• 无需显示进度；
• 只需要具有某种return.

• Quite short action, <1s;
• No need to deal with UI elements;
• One line command or such, so it looks inappropriate to extend AsyncTask with a new class;
• No need to be notified about the success of the task in an Activity or Fragment;
• No need to display progress;
• Just need to have some kind of return.

我最初的想法是:

boolean myReturn; new Thread(new Runnable() { public void run() { myReturn = myExtensiveTask(); } }).start(); public boolean myExtensiveTask() { ... }

这是否正确(甚至可能)?应该怎么做?

Would this be correct (or even possible)? How should this be done?

推荐答案

使用 bolts

Using the bolts utility framework (used by Facebook and parse), it is simple as that:

Task.callInBackground(new Callable<MyReturnType>() { @Override public MyReturnType call() { MyReturnType obj = doWork(); return obj; } });