Android上的HTTP POST请求

本文介绍了Android上的HTTP POST请求的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在过去的两小时，我一直试图做一个POST请求这个网页。的http：/ /www.halebop.se/butik/byt_behall_nummer/ 并试图向其发送的 numberToPort 。但是我得到了一堆饼干和一个302移动暂时回来了。

所有我想要做的就是发送一个带有编号的POST请求，并获得最后一页回来。在iOS上，我做到这一点使用ASIHTT prequest它处理重定向和饼干。

的iOS code：

的NSString * halebopURLString = @www.halebop.se/kontantkort/byt_behall_nummer/#ASIFormDataRequest *请求= [ASIFormDataRequest requestWithURL：[NSURL URLWithString：halebopURLString]];[要求setPostValue：halebopNumber forKey：@numberToPort];[要求setPostValue：@继续forKey：@行动];[要求setPostValue：@提交forKey：@提交];[请求startSynchronous]

我怎么做这在Android？

作为替代方案，一个PHP的解决方案是可接受的。

编辑：试过，它没有给输出及无异常。我有上网权限。预期结果：发送POST，获得302和饼干回来，发送cookie从302到URL并获得HTML背面（经过与萤火虫），但是我什么也得不到。

{尝试        InputStream的myInputStream = NULL;        URL网址;        URL =新的URL（www.halebop.se/kontantkort/byt_behall_nummer/#）;        HttpURLConnection的康恩=（HttpURLConnection类）url.openConnection（）;        conn.setDoOutput（真）;        conn.setInstanceFollowRedirects（真）;        conn.setRequestMethod（POST）;        OutputStreamWriter WR =新OutputStreamWriter（conn.getOutputStream（））;        wr.write（numberToPort =+ N +＆放大器;行动=继续和放大器;提交=提交）;        wr.flush（）;        myInputStream = conn.getInputStream（）;        wr.close（）;        RD的BufferedReader =新的BufferedReader（新的InputStreamReader（myInputStream），4096）;        串线;        StringBuilder的sbResult =新的StringBuilder（）;        而（（行= rd.readLine（））！= NULL）{            sbResult.append（线）;            Log.d（TAG，线+线）;        }        rd.close（）;        串contentOfMyInputStream = sbResult.toString（）;        Log.d（TAG，输出+ contentOfMyInputStream）;    }赶上（例外五）{        Log.d（TAG，e.getMessage（））;    }

解决方案

下面是如何设置岗位参数：

HttpPost httpost =新HttpPost（LOGIN_URL）;    清单＆LT;＆的NameValuePair GT; nvps =新的ArrayList＆LT;＆的NameValuePair GT;（）;    nvps.add（新BasicNameValuePair（测试1，测试1））;    nvps.add（新BasicNameValuePair（test2的，测试2））;            httpost.setEntity（新UrlEn codedFormEntity（nvps，HTTP.UTF_8））;    响应= GETRESPONSE（httpost）;

这里是详细解释关于code。

我还解释如何从你的回答中检索的HTTP cookies，并将它们设置成要求的这里

For the last two hours i've been trying to make a POST request to this page www.halebop.se/butik/byt_behall_nummer/ and tried to send numberToPort. However i get a bunch of cookies and a 302 moved temporarily back.

All i want to do is send the POST request with the number and get the final page back. On iOS, i do this using ASIHTTPRequest which handles the redirect and cookies.

iOS code:

NSString *halebopURLString = @"www.halebop.se/kontantkort/byt_behall_nummer/#"; ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:halebopURLString]]; [request setPostValue:halebopNumber forKey:@"numberToPort"]; [request setPostValue:@"continue" forKey:@"action"]; [request setPostValue:@"submit" forKey:@"submit"]; [request startSynchronous];

How do i do this on Android?

As an alternative, a PHP solution is acceptable.

Edit: Tried this, it gives no output and no exceptions. I have the internet permission. Expected result: Send POST, get 302 and cookies back, send cookies to URL from 302 and get HTML back (Checked with FireBug) however i get nothing.

try { InputStream myInputStream =null; URL url; url = new URL("www.halebop.se/kontantkort/byt_behall_nummer/#"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setDoOutput(true); conn.setInstanceFollowRedirects(true); conn.setRequestMethod("POST"); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write("numberToPort="+n+"&action=continue&submit=submit"); wr.flush(); myInputStream = conn.getInputStream(); wr.close(); BufferedReader rd = new BufferedReader(new InputStreamReader(myInputStream), 4096); String line; StringBuilder sbResult = new StringBuilder(); while ((line = rd.readLine()) != null) { sbResult.append(line); Log.d(TAG, "Line "+line); } rd.close(); String contentOfMyInputStream = sbResult.toString(); Log.d(TAG, "Output "+contentOfMyInputStream); } catch (Exception e) { Log.d(TAG,e.getMessage()); }

解决方案

Here is how you can set the post parameters:

HttpPost httpost = new HttpPost(LOGIN_URL); List <NameValuePair> nvps = new ArrayList <NameValuePair>(); nvps.add(new BasicNameValuePair("test1","test1" )); nvps.add(new BasicNameValuePair("test2", "test2" )); httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8)); response = getResponse(httpost);

Here is the detailed explanation about the code.

I also explained How to retrieve HTTP cookies from your response and set them into request here