Django Rest框架过滤器

本文介绍了Django Rest框架过滤器的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在使用由Django rest框架制成的API，我正在尝试过滤JSON 这是我的 serializers.py 文件

I'm working with API made from Django rest framework, I am trying to make a filter to a JSON This is my serializers.py file

from rest_framework import serializers from .models import Establecimiento,Categoria,Ciudad,Zona import django_filters class EstablecimientoSerializer(serializers.ModelSerializer): class Meta: model = Establecimiento depth = 1 fields = ('nombre', 'ciudad', 'categoria', 'direccion', 'telefono', 'precioMinimo', 'precioMaximo',)

和这是我的 views.py 文件

from rest_framework import viewsets from .serializers import EstablecimientoSerializer, CategoriaSerializer from models import * from rest_framework import filters from rest_framework import generics class EstablecimientoViewSet(viewsets.ModelViewSet): queryset = Establecimiento.objects.all() serializer_class = EstablecimientoSerializer filter_fields = ('categoria',)

然后在 EstablecimientoViewSet 类，我将 filter_fields =（'categoria'，） 过滤为带有类别字段的网址的API

Then in the EstablecimientoViewSet class, I put a filter_fields = ('categoria',) to filter the url's API with the category field

如果将过滤器添加到查询参数，结果集不会更改，它会显示所有未过滤的数据。

If I add the filter to the query parameters, the result set does not change, it shows all data unfiltered.

...establecimiento?establecimiento=bar

如何对该型号进行此过滤？

How can I make this filter about this model?

推荐答案

您需要定义过滤器后端和所有计划过滤的相关字段：

You need to define filter backend and all related fields you're planning to filter on:

class EstablecimientoViewSet(viewsets.ModelViewSet): filter_backends = (filters.DjangoFilterBackend,) filter_fields = ('categoria', 'categoria__titulo',)

示例：

URL?categoria__titulo=Categoria 1