本文介绍了PHP发布方法无法从URL获取数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个URL,该URL将用于粘贴并在浏览器中按Enter后获取帖子数据.我的链接是: vtrails.us/mixtape-builder/?song_urls=vtrails.us/wp-content/uploads/2015/12/mpthreetest.mp3&song_artist=ganja
I have an URL which is to be used for getting post data after pasting and pressing enter in the browser. My link is : vtrails.us/mixtape-builder/?song_urls=vtrails.us/wp-content/uploads/2015/12/mpthreetest.mp3&song_artist=ganja
<?php if(isset($_POST['song_urls']) && !empty($_POST['song_urls'])){ $song_url = $_POST['song_urls']; $song_artist = $_POST['song_artist']; } echo $song_url; echo $song_artist; ?>但是我什么都没收到.那我现在该怎么办?
But i am not getting any of them.So what can i do now?
推荐答案如果使用 $ _ GET 而不是 $ _ POST ,您将获得所需的结果:
If you use $_GET instead of $_POST you will get desired result:
这是代码
<?php if(isset($_POST['song_urls']) && !empty($_POST['song_urls'])){ $song_url = $_POST['song_urls']; $song_artist = $_POST['song_artist']; } echo $song_url; echo $song_artist; ?>更多推荐
PHP发布方法无法从URL获取数据
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