Django Forms：传递参数以形成

本文介绍了Django Forms：传递参数以形成的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

如何将参数传递给我的表单？

How do I pass a parameter to my form?

someView().. form = StylesForm(data_dict) # I also want to pass in site_id here. class StylesForm(forms.Form): # I want access to site_id here

根据以下答案编辑：

someView().. form = StylesForm(data_dict, site_id = 1) class StylesForm(forms.Form): def __init__(self,*args,**kwargs): self.site_id = kwargs.pop('site_id') super(StylesForm,self).__init__(*args,**kwargs) height = forms.CharField(widget=forms.TextInput(attrs={'size':site_id}))

推荐答案

你应该定义__init__您的表单的方法，如下所示：

You should define the __init__ method of your form, like that:

class StylesForm(forms.Form): def __init__(self,*args,**kwargs): self.site_id = kwargs.pop('site_id') super(StylesForm,self).__init__(*args,**kwargs)

当然，您无法访问self.site_id直到对象被创建，所以行：

of course you cannot access self.site_id until the object has been created, so the line:

height = forms.CharField(widget=forms.TextInput(attrs={'size':site_id}))

没有任何意义。您必须在窗体创建后将该属性添加到窗口小部件。尝试这样的东西：

makes no sense. You have to add the attribute to the widget after the form has been created. Try something like this:

class StylesForm(forms.Form): def __init__(self,*args,**kwargs): self.site_id = kwargs.pop('site_id') super(StylesForm,self).__init__(*args,**kwargs) self.fields['height'].widget = forms.TextInput(attrs={'size':site_id}) height = forms.CharField()

（未测试）