在Node.JS中向HTTP POST请求添加参数

本文介绍了在Node.JS中向HTTP POST请求添加参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我已经知道使用Node.js发送简单HTTP请求的方法如下：

I've known the way to send a simple HTTP request using Node.js as the following:

var http = require('http'); var options = { host: 'example', port: 80, path: '/foo.html' }; http.get(options, function(resp){ resp.on('data', function(chunk){ //do something with chunk }); }).on("error", function(e){ console.log("Got error: " + e.message); });

我想知道如何在 POST的主体中嵌入参数请求以及如何从接收器模块捕获它们。

I want to know how to embed parameters in the body of POST request and how to capture them from the receiver module.

推荐答案

你介意使用请求库。发送帖子请求就像

Would you mind using the request library. Sending a post request becomes as simple as

var options = { url: 'someurl', 'method': 'POST', 'body': {"key":"val"} }; request(options,function(error,response,body){ //do what you want with this callback functon });

请求库还有一个快捷方式，可以在 request.post中发布帖子您传递网址以发送帖子请求以及要发送到该网址的数据的方法。

The request library also has a shortcut for post in request.post method in which you pass the url to make a post request to along with the data to send to that url.

根据评论进行修改

要捕获一个帖子请求，它会如果您使用某种框架，那就最好了。由于 express 是最受欢迎的，我将以快递为例。如果您不熟悉快递，我建议您阅读作者自己的入门指南 。

To "capture" a post request it would be best if you used some kind of framework. Since express is the most popular one I will give an example of express. In case you are not familiar with express I suggest reading a getting started guide by the author himself.

您需要做的就是创建一个邮政路线，回调函数将包含发布到该网址的数据

All you need to do is create a post route and the callback function will contain the data that is posted to that url

app.post('/name-of-route',function(req,res){ console.log(req.body); //req.body contains the post data that you posted to the url });