这是我的XML字符串:
This is my XML string:
<root>EXTRA <elem id="123" at="abc">HelloText</elem> </root>如何将其转换为JSON格式(带有属性和HelloText)?
How can I convert it to a JSON format (WITH attributes and HelloText) ?
推荐答案因为RJS不想检查我向他建议的答案,所以它来自这篇文章:
Because RJS doesn't want to check the answer i suggested to him, here is it from this post:
一个常见的陷阱是忘记json_encode()不尊重具有textvalue和attribute的元素.它将选择其中之一,即数据丢失.下面的功能解决了这个问题.如果决定使用json_encode/decode方式,建议使用以下功能.
A common pitfall is to forget that json_encode() does not respect elements with a textvalue and attribute(s). It will choose one of those, meaning dataloss. The function below solves that problem. If one decides to go for the json_encode/decode way, the following function is advised.
function json_prepare_xml( $domNode ){ foreach( $domNode->childNodes as $node) if($node->hasChildNodes()) json_prepare_xml($node); if( $domNode->hasAttributes() && strlen($domNode->nodeValue) ){ $domNode->setAttribute("nodeValue", $node->textContent ); $node->nodeValue = ""; } return $node; } $dom->loadXML( file_get_contents($xmlfile) ); json_prepare_xml($dom); $sxml = simplexml_load_string( $dom->saveXML() ); $json = json_decode( json_encode( $sxml ) ) );这样做,<foo bar="3">Lorem</foo>在您的JSON中将不会以{"foo":"Lorem"}结尾.
by doing so, <foo bar="3">Lorem</foo> will not end up as {"foo":"Lorem"} in your JSON.
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