如何获取完整分辨率的instagram个人资料的个人资料图片? (旧的URL方案今天停止工作.)
how do I get the profile picture of an instagram profile in full-res? (The old URL scheme stopped working today).
regex ='profile_pic_url_hd:"([[0-9a-zA-Z ._-/:] *),'
regex='profile_pic_url_hd":"([0-9a-zA-Z._-/:]*)",'
正在处理320像素的图片,但仅此而已. 150x150 img的前缀不同,但是带有jpg的URL的ID/结尾是相同的.
Is working for 320px pictures, but nothing else. The prefix to the 150x150 img is different, but the ID/ending of the url with jpg is the same.
谢谢
推荐答案好的,我找到了最终解决方案:
Okay guys I found a final solution:
使用此链接user_id noreferrer> www.instagram/{name}/?__ a = 1
Get the user_id of the account using this link www.instagram/{name}/?__a=1
使用上面 i.instagram/api/v1/users/{user_id}/info/ 完整的个人资料图片链接可以在 [hd_profile_pic_url_info] [url]
Visit this JSON-API with the user_id above i.instagram/api/v1/users/{user_id}/info/ The full size profile picture link can be found in [hd_profile_pic_url_info][url]
就是这样! :)
如果步骤 1 不起作用,我的PHP解决方案将获取用户ID :
If step 1 doesn't work, my Php solution to get the user-id:
$name = "{username}"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "www.instagram/$name/"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); $result = curl_exec($ch); $http = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); if($http=="200") { $doc = new DOMDocument(); $doc->loadHTML($result); $xpath = new DOMXPath($doc); $js = $xpath->query('//body/script[@type="text/javascript"]')->item(0)->nodeValue; $start = strpos($js, '{'); $end = strrpos($js, ';'); $json = substr($js, $start, $end - $start); $data = json_decode($json, true); $user_id = $data["entry_data"]["ProfilePage"][0]["graphql"]["user"]["id"]; }我正在HTML文档中搜索用户ID.
I'm searching in the HTML document for user-id.
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Instagram个人资料图片是否具有完整分辨率?
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