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问题描述
下面的函数foo返回字符串'foo'.如何获取从线程目标返回的值'foo'?
The function foo below returns a string 'foo'. How can I get the value 'foo' which is returned from the thread's target?
from threading import Thread def foo(bar): print('hello {}'.format(bar)) return 'foo' thread = Thread(target=foo, args=('world!',)) thread.start() return_value = thread.join()上面显示的一种显而易见的方法"不起作用:thread.join()返回了None.
The "one obvious way to do it", shown above, doesn't work: thread.join() returned None.
推荐答案在Python 3.2+中,stdlib concurrent.futures 模块为threading提供了更高级别的API,包括将返回值或异常从工作线程传递回主线程:
In Python 3.2+, stdlib concurrent.futures module provides a higher level API to threading, including passing return values or exceptions from a worker thread back to the main thread:
import concurrent.futures def foo(bar): print('hello {}'.format(bar)) return 'foo' with concurrent.futures.ThreadPoolExecutor() as executor: future = executor.submit(foo, 'world!') return_value = future.result() print(return_value)更多推荐
如何从python中的线程获取返回值?
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