我正在创建一个Android应用，以将JSON发送到服务器端php脚本并将其存储在数据库中
I'm creating an android app to send JSON to a server-side php script and store it in a database
这是应用程序中的相关代码
Here's the relevant code from the app
public String POST(){ String url = "192.168.150.1/t2.php"; InputStream inputStream = null; String result = ""; try { HttpClient httpclient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); String json = ""; JSONObject jsonObject = new JSONObject(); jsonObject.put("str", "bang"); jsonObject.put("lat", 3.10); jsonObject.put("lon", 3.10); json = jsonObject.toString(); Toast.makeText(this, json, Toast.LENGTH_LONG).show(); StringEntity se = new StringEntity(json); httpPost.setEntity(se); httpPost.setHeader("Accept", "application/json"); httpPost.setHeader("Content-type", "application/json"); HttpResponse httpResponse = httpclient.execute(httpPost); inputStream = httpResponse.getEntity().getContent(); if(inputStream != null) result = "success"; else result = "Did not work!"; } catch (Exception e) { Log.d("InputStream", e.getLocalizedMessage()); } return result; }这是php脚本
<?php $connection = mysql_connect("192.168.150.1","****","****"); if (!$connection) { die("Database connection failed: " . mysql_error()); } echo "connection success\n"; $db_select = mysql_select_db("ps1",$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } echo "db selections success"; ?> <html> <head> <title> hl</title> </head> <body> <p>hello</p> <?php $js = json_decode(file_get_contents('php://input')); //$js = json_decode($_POST); ------------ ****** $atr =''; $val = ''; foreach ($js as $a => $v) { $atr = $atr.','.$a; $val = $val.','.$v; } $atr = ltrim($atr,','); $val = ltrim($val,','); echo "insert into js (".$atr.") values (" .$val . ");"; $result = mysql_query("insert into js (".$atr.") values (" .$val . ");", $connection); if (!$result) { die("Database query failed: " . mysql_error()); } ?> </body> </html> <?php mysql_close($connection); ?>现在，如果尝试从应用程序的对象发送JSON，则什么都不会发生
Now if try to send a JSON from object from the app, nothing happens
但如果我尝试
curl -H内容类型:application/json" -d'{"str":"\" hello \"，"lat":"3.1"，"lon":"5.2"}'localhost/t2.php
curl -H "Content-Type: application/json" -d '{"str":"\"hello\"","lat":"3.1","lon":"5.2"}' localhost/t2.php
在命令行中有效.
如果我尝试取消注释$ js = json_decode($ _ POST);在PHP脚本中插入一行，并注释掉php://input行，然后不传输JSON对象，而是将值"，0,0插入数据库中
Also if I try to uncomment the $js = json_decode($_POST); line in the PHP script and comment out the php://input line, then the JSON object is not transferred but the values "", 0,0 are inserted into the database
我认为应用程序代码一定有错误.我正在从此处 hmkcode/android-send-json-data-to-server/
I think there must be an error with the app code.I'm following the tutorial and code from here hmkcode/android-send-json-data-to-server/
问题
谢谢
查询
推荐答案使用此方法发出POST请求:
Use this method to make POST Request :
public String makePOSTRequest(String url, List<NameValuePair> nameValuePairs) { String response = ""; try { HttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); response = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } Log.d(LOGTAG, "POST Response >>> " + response); return response; }用法:
在Java中:
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("json",jsonObject.toString())); String response = makePOSTRequest(String url, nameValuePairs );服务器端PHP:
$jsonInput = $_POST['json']; json_decode($jsonInput);更多推荐
在android应用中使用POST将JSON发送到服务器
发布评论