app.post不是函数表达节点

本文介绍了app.post不是函数表达节点的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在server.js中拥有所有路由，但我想将其模块化并放入名为routes的文件夹中。我在routes文件夹中创建了一个名为apis.js的文件但是我这样做了 TypeError：app.post不是函数

I had all my routes in server.js but I wanted to make it modular and put into a folder called routes. I created a file called apis.js in routes folder but as I did that I get TypeError: app.post is not a function

server.js：

server.js:

var express = require('express'); var app = express(); var bodyParser = require('body-parser'); var urlencode = bodyParser.urlencoded({ extended: true}); app.use(express.static('public')); var apis = require('./routes/apis'); app.use('/', apis); module.exports = app;

apis.js：

module.exports = function(app){ app.get('/', function(req, res) { res.send('OK'); }); app.post('/idea', function(req, res) { ... }); };

另外，拥有 module.exports = app 在server.js中很重要，因为我有测试运行，我每次都想要一个app实例。

Also, having module.exports = app in server.js is important as I have tests running and I want a instance of app everytime.

我缺少什么？

推荐答案

更好的方法： -

server.js

server.js

var express = require('express'); var app = express(); var bodyParser = require('body-parser'); var urlencode = bodyParser.urlencoded({ extended: true}); app.use(express.static('public')); var apis = require('./routes/apis'); app.use('/', apis); module.exports = app;

apis.js： -

apis.js :-

var router = require('express').Router(); router.post('/url',function(req,res,next){ //your code }) module.exports = router