处理 urllib2 的超时?

本文介绍了处理 urllib2 的超时?- Python的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在 urllib2 的 urlopen 中使用超时参数.

I'm using the timeout parameter within the urllib2's urlopen.

urllib2.urlopen('www.example', timeout=1)

如何告诉 Python 如果超时到期，应该引发自定义错误?

How do I tell Python that if the timeout expires a custom error should be raised?

有什么想法吗?

推荐答案

在极少数情况下您要使用 ，除了:.这样做会捕获任何异常，这可能很难调试，并且它会捕获包括 SystemExit 和 KeyboardInterupt 在内的异常，这会使您的程序烦人使用..

There are very few cases where you want to use except:. Doing this captures any exception, which can be hard to debug, and it captures exceptions including SystemExit and KeyboardInterupt, which can make your program annoying to use..

最简单的情况是，您会发现 urllib2.URLError:

At the very simplest, you would catch urllib2.URLError:

try: urllib2.urlopen("example", timeout = 1) except urllib2.URLError, e: raise MyException("There was an error: %r" % e)

以下应捕获连接超时时引发的特定错误:

The following should capture the specific error raised when the connection times out:

import urllib2 import socket class MyException(Exception): pass try: urllib2.urlopen("example", timeout = 1) except urllib2.URLError, e: # For Python 2.6 if isinstance(e.reason, socket.timeout): raise MyException("There was an error: %r" % e) else: # reraise the original error raise except socket.timeout, e: # For Python 2.7 raise MyException("There was an error: %r" % e)