我在 urllib2 的 urlopen 中使用超时参数.
I'm using the timeout parameter within the urllib2's urlopen.
urllib2.urlopen('www.example', timeout=1)如何告诉 Python 如果超时到期,应该引发自定义错误?
How do I tell Python that if the timeout expires a custom error should be raised?
有什么想法吗?
推荐答案在极少数情况下您要使用 ,除了:.这样做会捕获任何异常,这可能很难调试,并且它会捕获包括 SystemExit 和 KeyboardInterupt 在内的异常,这会使您的程序烦人使用..
There are very few cases where you want to use except:. Doing this captures any exception, which can be hard to debug, and it captures exceptions including SystemExit and KeyboardInterupt, which can make your program annoying to use..
最简单的情况是,您会发现 urllib2.URLError:
At the very simplest, you would catch urllib2.URLError:
try: urllib2.urlopen("example", timeout = 1) except urllib2.URLError, e: raise MyException("There was an error: %r" % e)以下应捕获连接超时时引发的特定错误:
The following should capture the specific error raised when the connection times out:
import urllib2 import socket class MyException(Exception): pass try: urllib2.urlopen("example", timeout = 1) except urllib2.URLError, e: # For Python 2.6 if isinstance(e.reason, socket.timeout): raise MyException("There was an error: %r" % e) else: # reraise the original error raise except socket.timeout, e: # For Python 2.7 raise MyException("There was an error: %r" % e)更多推荐
处理 urllib2 的超时?
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