我试图提取URL请求的响应头。当我使用firebug分析URL请求的响应输出时，它会返回：
I'm trying to extract the response header of a URL request. When I use firebug to analyze the response output of a URL request, it returns:
Content-Type text/html然而，当我使用python代码时：
However when I use the python code:
urllib2.urlopen(URL).info()结果输出返回：
Content-Type: video/x-flv我对python和一般的web编程都很陌生;任何有用的见解，非常感谢。此外，如果需要更多信息，请让我知道。
I am new to python, and to web programming in general; any helpful insight is much appreciated. Also, if more info is needed please let me know.
感谢您阅读本文
推荐答案尝试像Firefox那样请求。您可以在Firebug中看到请求标题，因此将它们添加到您的请求对象中：
Try to request as Firefox does. You can see the request headers in Firebug, so add them to your request object:
import urllib2 request = urllib2.Request('your.tld/...') request.add_header('User-Agent', 'some fake agent string') request.add_header('Referer', 'fake referrer') ... response = urllib2.urlopen(request) # check content type: print response.info().getheader('Content-Type')还有HTTPCookieProcessor，它可以让它变得更好，但我不认为大多数情况下你都需要它。看看python的文档：
There's also HTTPCookieProcessor which can make it better, but I don't think you'll need it in most cases. Have a look at python's documentation:
http ：//docs.python/library/urllib2.html
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Python urllib2响应头
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