同步线程以进行pthread

本文介绍了同步线程以进行pthread_cond_broadcast调用的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个带有管理器"线程的简单应用程序，它产生了十个简单的工人"线程.我希望所有工作者"线程都在同一条件变量(即condvar)上阻塞，并且我想通过pthread_cond_broadcast调用手动通知所有十个线程同时唤醒.

I have a simple application with a "manager" thread that spawns ten simple "worker" threads. I want all of the "worker" threads to block on the same condition variable (ie: condvar), and I want to manually signal all ten threads to wake up at the same time with a pthread_cond_broadcast call.

在我的应用程序中，线程可能会遇到错误情况并提早终止，因此有可能不是所有十个线程都将其到达同步点.

In the case of my application, it is possible for threads to suffer an error condition and terminate early, so it is possible that not all ten threads make it to the synchronization point.

一种简单的机制是创建一个pthread_barrier_t并让所有十个线程调用pthread_barrier_wait，并且当所有十个线程完成此调用时，它们都可以自由地继续执行.但是，这将要求线程能够修改屏障需要解除阻塞的线程数.我不知道这是否可以安全地修改.

One simple mechanism would be to create a pthread_barrier_t and have all ten threads call pthread_barrier_wait, and when all ten threads complete this call, they are all free to continue execution. However, this would require the threads being able to modify the number of threads the barrier requires to unblock. I don't know if this can be safely modified.

此外，我想保证所有仍在工作的线程不会像使用屏障那样自动启动，而是想通过pthread_cond_broadcast调用手动启动它们.在发出广播呼叫之前，如何保证所有仍处于活动状态的线程(最好是十个)在condvar上已阻塞?

Additionally, I want to guarantee all the still-working threads not start automatically like they would with a barrier, I want to manually start them with a pthread_cond_broadcast call instead. How would I guarantee that all the threads that are still alive (ideally ten) have blocked on the condvar before I made the broadcast call?

谢谢！

推荐答案

下面显示了一种使用条件变量和其他一些变量的方法；尽管可能有更好的方法.注释应显示其工作方式.当然，您必须修改一些东西以适合您的实际情况.例如可能涉及循环等等.

The following shows one way to do it, using a condition variable and a few other variables; though there may be better ways. The comments should show how it works. You'd have to modify things to suit your actual situation of course; for instance there might be loops involved, etc.

int activeThreads = 0; /* number of threads currently going */ int waitingThreads = 0; /* number of threads waiting on the condition */ int readyFlag = 0; /* flag to tell the threads to proceed when signaled */ pthread_cond_t cond; /* condition to wait on / signal */ pthread_mutex_t mtx; /* mutex for the above */ pthread_cond_t condWaiting; /* EDIT: additional condition variable to signal * when each thread starts waiting */ void *threadFunc(void *arg) { /* Edit: Rather than incrementing 'activeThreads' here, it should be done * in the main thread when each thread is created (to avoid a race) */ /* ...do stuff... */ /* When the threads should wait, do this (they wait for 'readyFlag' to be * set, but also adjust the waiting thread count so the main thread can * determine whether to broadcast) */ pthread_mutex_lock(&mtx); if (readyFlag == 0) { waitingThreads++; do { pthread_cond_signal(&condWaiting); /* EDIT: signal the main thread when * a thread begins waiting */ pthread_cond_wait(&cond,&mtx); } while (readyFlag == 0); waitingThreads--; } pthread_mutex_unlock(&mtx); /* ...more stuff... */ /* When threads terminate, they decrement the active thread count */ pthread_mutex_lock(&mtx); activeThreads--; pthread_cond_signal(&condWaiting); /* EDIT: also signal the main thread * when a thread exits to make it * recheck the waiting thread count if * waiting for all threads to wait */ pthread_mutex_unlock(&mtx); return NULL; } int main(int argc, char *argv[]) { /* Edit: Showing some code to initialize the mutex, condition variable(s), * etc., and create some threads -- modify as needed */ pthread_mutex_init(&mtx,NULL); pthread_cond_init(&cond,NULL); pthread_cond_init(&condWaiting,NULL); /* EDIT: if main thread should block * until all threads are waiting */ activeThreads = waitingThreads = readyFlag = 0; /* Edit: Increment 'activeThreads' here rather than in the thread function, * to avoid a race (if the main thread started waiting for the others * when not all had incremented the count yet, the main thread might end * up waiting for fewer threads to be ready -- though it's unlikely */ #define NUM_THREADS 10 pthread_t workers[NUM_THREADS]; for (int i = 0; i < NUM_THREADS; i++) { /* should use appropriate thread attributes */ if (pthread_create(&workers[i],NULL,threadFunc,NULL) == 0) activeThreads++; } /* ...do stuff... */ /* Set 'readyFlag' and do condition broadcast IF all threads are waiting, * or just carry on if they aren't */ pthread_mutex_lock(&mtx); if ((activeThreads != 0) && (activeThreads == waitingThreads)) { readyFlag = 1; pthread_cond_broadcast(&cond); } pthread_mutex_unlock(&mtx); /* EDIT: OR.. to wait until all threads are waiting and then broadcast, do * this instead: */ pthread_mutex_lock(&mtx); while (waitingThreads < activeThreads) { /* wait on 'condWaiting' until all * active threads are waiting */ pthread_cond_wait(&condWaiting,&mtx); } if (waitingThreads != 0) { readyFlag = 1; pthread_cond_broadcast(&cond); } pthread_mutex_unlock(&mtx); /* ...more stuff... */ /* If needed, you can clear the flag when NO threads are waiting.. */ pthread_mutex_lock(&mtx); if (waitingThreads == 0) readyFlag = 0; pthread_mutex_unlock(&mtx); /* ...even more stuff... */ return 0; }

不过，我要补充一点的是，我不知道何时有充分的理由这样做，而不仅仅是以更直接的方式保护资源.

I'd add, though, that I don't see when there'd be a good reason to do this rather than just protecting resources in a more straightforward way.

向代码中添加了一些内容，显示了第二个条件变量，用于让主线程等待所有工作程序就绪.更改的部分在注释中标记为""，如果不需要，可以将其省略.我还通过将activeThreads的增量移出线程函数来纠正了竞争状况，并显示了互斥锁等的初始化(没有错误处理).

Added some things to the code, showing a second condition variable used to let the main thread wait for all the workers to be ready. The changed parts are marked with "" in comments, and can be left out if not needed. I've also corrected a race condition by moving the increment of activeThreads out of the thread function, and shown the initialization for the mutex, etc. (without error handling).